Answer:
Examples of input devices include keyboards, mice, scanners, digital cameras and joysticks.
Explanation:
What happened if the offshore team members are not able to participate in the iterations demo due to timezone/infrastructure issues-(c) No Major issue. Since offshore lead and onsite members participate in the demo with the product owner, they can cascade the feedback back to the offshore members.
Explanation:
<u>No Major issue. Since offshore lead and onsite members participate in the demo with the product owner, they can cascade the feedback back to the offshore members.</u>
From the above statement it is clear that in case the offshore team members are not able to participate in the demo with the product owner due to timezone/infrastructure issues it want be a big issue since the onsite members of the team will participate in the demo and they can give all the valuable knowledge and feedback to the offshore members.As they all are part of the very same team
<u>Hence the option(3) is the correct option</u>
Answer:
The Correct answer for the given question is "elements " .
Explanation:
The number of bytes is always multiple by the number of array elements in an array to getting total memory occupy by any array .
For example :
int a[100];
Since in c language int is 2 bytes
So memory in number of bytes =2*100=200 bytes
Indexes is keep the track of physical location of any file this is also used to track the logical location of file in database so this option is wrong
Subscripts are the index number of an array so we will never used subscripts to getting total memory occupy by any array so this option is wrong
Iterators are the loop so this option is wrong.
Due to this the correct answer is elements.
Answer:
adds up the values in the range of cells provided
Explanation:
Answer:
public class Main
{
// required method
public static void fizzBuzz(){
// looping through 1 to 100
for(int i = 1; i <= 100; i++){
//if number is evenly divisible by both 3 and 5
if(i%3 == 0 && i%5 == 0){
System.out.println("fiz buzz");
}
// if number is divisible by 3
else if (i%3 == 0){
System.out.println("fizz");
}
// if number is divisible by 5
else if (i%5 == 0){
System.out.println("buzz");
}
// if number is not divisible by both 3 and 5
else {
System.out.println(i);
}
}
}
// main method
public static void main(String[] args) {
//calling function
fizzBuzz();
}
}
Explanation:
