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finlep [7]
3 years ago
11

Please help with this problem

Mathematics
1 answer:
GrogVix [38]3 years ago
6 0
The correct answer is B. 8<=l<=10. You can find this because we know the length is 2 feel more than the width, so when the length is provided, we can find the area. 8*6 is 48, which is the minimum area, and 10*8 is 80, which is the maximum area allowed.
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1+1? Will give brainliest to first correct answer.
d1i1m1o1n [39]

Answer:

1+1= 2

have a nice day stay safe

3 0
3 years ago
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Your parents decide they would like to install a rectangular swimming pool in the backyard. There is a 15-foot by 20-foot rectan
Lilit [14]

Answer:

  • perimeter: 46 ft
  • area: 126 ft²

Step-by-step explanation:

Since the 3 ft edge is on both sides of the pool, each dimension of the pool is 6 ft shorter than the corresponding dimension of the space. The pool will be 15 ft -6 ft = 9 ft in one direction and 20 ft -6 ft = 14 ft in the other direction.

The perimeter of the pool is the sum of its side lengths:

  P = 9 ft + 14 ft + 9 ft + 14 ft = 2(9 ft +14 ft) = 2(23 ft)

  P = 46 ft

__

The area of the pool is the product of its length and width:

  A = (14 ft)(9 ft) = 126 ft²

The perimeter and area are 46 ft and 126 ft², respectively.

5 0
3 years ago
Alina has just received 3 video games for her birthday to add to her existing 12 video games. A week later she went to the thrif
amm1812
She should have a total of 35 games by now.
4 0
3 years ago
Read 2 more answers
How to solve an expression with variables in the exponents?
gtnhenbr [62]

Answer:

  use logarithms

Step-by-step explanation:

Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.

__

You will note that this approach works well enough for ...

  a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents

  (x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs

but doesn't do anything to help you solve ...

  x +3 = b^(x -6)

There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.

__

Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.

In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.

8 0
3 years ago
Is 3/5 + 3/5 negative or positive <br> ​<br> ​<br> ​
Elan Coil [88]

Answer:

positive

Step-by-step explanation:

when there is no sign in front of the numbers, we can assume that the numbers are positive

8 0
2 years ago
Read 2 more answers
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