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disa [49]
2 years ago
7

Help me please I dont know this​

Mathematics
2 answers:
mihalych1998 [28]2 years ago
8 0

Answer:

answer: 384

Step-by-step explanation:

Hello! cubes are very simple! since there all the same measure and 6 faces all we have to do is 8 × 8 = 64 sense we know 1 face is 64 we just have to multiply by 6 cause there is 6 faces so

64 × 6 = 384 Hope this helps you!

Firdavs [7]2 years ago
5 0
I’m pretty sure it’s 24
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The ratio of boys to girls at the beach cleanup was 7.8. If there are 42 boys how many girls are there?
Mars2501 [29]
If the ratio is 7:8, and the number of boys is 42, you would do 42 divided by 7, which equals 6. Then you do 8 times 6, and that's equal to 48. So the ratio is 42:48, with an amount of 48 girls.
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3 years ago
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What is the simplest form for 3/8
Maslowich
So, 3 goes into 8 2 times and 2 will be left over so you would put:
2 2/8 or 2 1/4

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3 years ago
I've been workin and workin and kept on gettin 21...but the answer key says 27. If yea could help and explain this I'd surely lo
lilavasa [31]

q/3 - 3 =6

add 3 to each side

q/3 = 9

multiply both sides by 3

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7 0
3 years ago
Let X denote the length of human pregnancies from conception to birth, where X has a normal distribution with mean of 264 days a
Kaylis [27]

Answer:

Step-by-step explanation:

Hello!

X: length of human pregnancies from conception to birth.

X~N(μ;σ²)

μ= 264 day

σ= 16 day

If the variable of interest has a normal distribution, it's the sample mean, that it is also a variable on its own, has a normal distribution with parameters:

X[bar] ~N(μ;σ²/n)

When calculating a probability of a value of "X" happening it corresponds to use the standard normal: Z= (X[bar]-μ)/σ

When calculating the probability of the sample mean taking a given value, the variance is divided by the sample size. The standard normal distribution to use is Z= (X[bar]-μ)/(σ/√n)

a. You need to calculate the probability that the sample mean will be less than 260 for a random sample of 15 women.

P(X[bar]<260)= P(Z<(260-264)/(16/√15))= P(Z<-0.97)= 0.16602

b. P(X[bar]>b)= 0.05

You need to find the value of X[bar] that has above it 5% of the distribution and 95% below.

P(X[bar]≤b)= 0.95

P(Z≤(b-μ)/(σ/√n))= 0.95

The value of Z that accumulates 0.95 of probability is Z= 1.648

Now we reverse the standardization to reach the value of pregnancy length:

1.648= (b-264)/(16/√15)

1.648*(16/√15)= b-264

b= [1.648*(16/√15)]+264

b= 270.81 days

c. Now the sample taken is of 7 women and you need to calculate the probability of the sample mean of the length of pregnancy lies between 1800 and 1900 days.

Symbolically:

P(1800≤X[bar]≤1900) = P(X[bar]≤1900) - P(X[bar]≤1800)

P(Z≤(1900-264)/(16/√7)) - P(Z≤(1800-264)/(16/√7))

P(Z≤270.53) - P(Z≤253.99)= 1 - 1 = 0

d. P(X[bar]>270)= 0.1151

P(Z>(270-264)/(16/√n))= 0.1151

P(Z≤(270-264)/(16/√n))= 1 - 0.1151

P(Z≤6/(16/√n))= 0.8849

With the information of the cumulated probability you can reach the value of Z and clear the sample size needed:

P(Z≤1.200)= 0.8849

Z= \frac{X[bar]-Mu}{Sigma/\sqrt{n} }

Z*(Sigma/\sqrt{n} )= (X[bar]-Mu)

(Sigma/\sqrt{n} )= \frac{(X[bar]-Mu)}{Z}

Sigma= \frac{(X[bar]-Mu)}{Z}*\sqrt{n}

Sigma*(\frac{Z}{(X[bar]-Mu)})= \sqrt{n}

n = (Sigma*(\frac{Z}{(X[bar]-Mu)}))^2

n = (16*(\frac{1.2}{(270-264)}))^2

n= 10.24 ≅ 11 pregnant women.

I hope it helps!

6 0
3 years ago
Determine the volume of this prism
nikdorinn [45]

Answer:

200cm cubed

Step-by-step explanation:

Remember that volume of a rectangular prism is length x width x height

4 0
2 years ago
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