Question

Jules kicks a soccer ball off the ground and into the air with an initial velocity of 25 feet per second. Assume the starting height of the ball is 0 feet. Approximately what maximum height does the soccer ball reach? (1 point)

Answer 1

Hello,

y=-g/2 t²+25 t is the trajectoire with g=9.81 m/s²

y=-g/2 (t²-25*2/g t)
==>y=-g/2(t²-2*25/g t +25²/g²)+25²/g² * g/2
==>y=-g/2(t-25/g)²+25²/(2g)

==> h=25²/(2g)=625/(2*9.81*3.28084)=9,709479... feet
(for 1m=3.28084 feet)