Hi there! The answer is y = 1/6x + 1/2
To find the inverse function x and y need to switch places.

Now rewrite the equation, until it will be in standard form (slope-intercept form) again.

Add 3.

Switch sides.

Divide both sides by 6.

Hence, the answer is y = 1/6x + 1/2.
~ Hope this helps you!
Answer:
f(2n)-f(n)=log2
b.lg(lg2+lgn)-lglgn
c. f(2n)/f(n)=2
d.2nlg2+nlgn
e.f(2n)/(n)=4
f.f(2n)/f(n)=8
g. f(2n)/f(n)=2
Step-by-step explanation:
What is the effect in the time required to solve a prob- lem when you double the size of the input from n to 2n, assuming that the number of milliseconds the algorithm uses to solve the problem with input size n is each of these function? [Express your answer in the simplest form pos- sible, either as a ratio or a difference. Your answer may be a function of n or a constant.]
from a
f(n)=logn
f(2n)=lg(2n)
f(2n)-f(n)=log2n-logn
lo(2*n)=lg2+lgn-lgn
f(2n)-f(n)=lg2+lgn-lgn
f(2n)-f(n)=log2
2.f(n)=lglgn
F(2n)=lglg2n
f(2n)-f(n)=lglg2n-lglgn
lg2n=lg2+lgn
lg(lg2+lgn)-lglgn
3.f(n)=100n
f(2n)=100(2n)
f(2n)/f(n)=200n/100n
f(2n)/f(n)=2
the time will double
4.f(n)=nlgn
f(2n)=2nlg2n
f(2n)-f(n)=2nlg2n-nlgn
f(2n)-f(n)=2n(lg2+lgn)-nlgn
2nLg2+2nlgn-nlgn
2nlg2+nlgn
5.we shall look for the ratio
f(n)=n^2
f(2n)=2n^2
f(2n)/(n)=2n^2/n^2
f(2n)/(n)=4n^2/n^2
f(2n)/(n)=4
the time will be times 4 the initial tiote tat ratio are used because it will be easier to calculate and compare
6.n^3
f(n)=n^3
f(2n)=(2n)^3
f(2n)/f(n)=(2n)^3/n^3
f(2n)/f(n)=8
the ratio will be times 8 the initial
7.2n
f(n)=2n
f(2n)=2(2n)
f(2n)/f(n)=2(2n)/2n
f(2n)/f(n)=2
Answer:
To do this, all you need is to draw triangle with each side being 7 cm, and a circle that intersects all three of its corners.
Step-by-step explanation:
- With a ruler and a pencil, draw a 7cm line.
- With a compass set to a radius of 7cm draw an arc centered around the right end of the line.
- With the same compass, still at 7cm, draw an arc centered around the left end of the line.
- These two arcs will intersect on either side of the line (you only need one side, so you only need a small arc in the right place, roughly where you think the third point if the triangle is.
- Where those arcs intersect is the third point on your triangle. Mark that, and then trace two lines from that point to either end of the line segment you started with.
<em>You now have an equilateral triangle with 7cm sides. Next you need to draw the circle</em>
- Measure the halfway point on two of your three lines.
- Draw a line from that each of those halfway points to the opposite corner. The new lines you're drawing will be perpendicular to the edge your measuring against.
- You have now drawn two line segments, and they intersect in the center of the circle. Now take your compass and set its radius to the distance from that center point to one of the three corner points.
- Centered on that middle point, trace a circle with the selected radius.
And you're done!
Answer:
32
Step-by-step explanation:
The equation
and the graph below describe the velocity V in feet per second of a ball <em>t</em> seconds after it is shot into the air.
To find the balls velocity after seven seconds, substitute t = 7 into the function expression:
