Question

The tank of the air compressor is subjected to an internal pressure of 90 psi. If the inner diameter of the tank is 22 in., and the wall thickness is 0.25 in., determine the stress components acting at point A. Draw a volume element of the material at this point, and show the results on the element (outer wall).
What would be the maximum shear that this material would experience?

Answer 1

Answer:

б₁ = 1.98 ksi

б₂ = 1.98 ksi

Explanation:

Calculating the component of stress acting at point A using circumferential stress equation, we have;

б₁ = p*r/t

   = 90*11/0.25

   = 3960 psi = 3.96 ksi

Calculating the component of stress acting at point A using longitudinal stress equation, we have;

б₂ = p*r/2*t

    = 90*11 /2*0.25

    = 1.98 ksi

Find attached of the volume element at point A.