Answer:
i dont know th answer can u help ?
Explanation:
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The sample of 81 students was selected with a mean score of 90, this illustrates an example of a right tailed one sample z test.
<h3>How to illustrate the sample?</h3>
From the information given, the teacher claims that the mean score of students in his class is greater than 82 with a standard deviation of 20. In this case, the right tailed one sample z test is used.
The z value will be:
= (90 - 82)/20/✓81
= 3.6
Since 3.6 > 1.645, the null hypothesis will be rejected as there's enough evidence to support the teacher's claim.
When an online medicine shop claims that the mean delivery time for medicines is less than 120 minutes with a standard deviation of 30 minutes, the left tailed one sample test is used.
The z value will be:
= (100 - 120)/(30/✓49)
= -4.66
The null hypothesis is rejected as there is enough evidence to support the claim of the medicine shop.
Learn more about sampling on:
brainly.com/question/17831271
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Answer:
The maximum possible volume flow of gasoline is 0.543 m^3/s
Explanation:
Power = pressure differential × volume flow rate
Power = 3.8 kW
Pressure differential = 7 kPa
Volume flow rate = power ÷ pressure differential = 3.8 ÷ 7 = 0.543 m^3/s
Answer:
i) 3750 veh/hr/ln
ii) 100 veh/mi/In
iii) 37.5 mph
Explanation:
number of lanes = 3
sf for both directions = 75 mph ( free mean speed )
Dj for both directions = 200 veh/mi/In
<u>Calculate the value of S0, D0 (veh/mi/ln) and maximum Vm (veh/hr)</u>
For either direction we will consider the total volume = 3 lanes
value of Dj = 3 lanes * 200 = 600 veh/mi/
i) value of SO
= ( Dj * sf ) / 4 = ( 600 * 75 ) / 4 = 11250 veh/hr = 3750 veh/hr/lane
ii) Value of DO
DO = Dj / 2 = 200 /2 = 100 veh/mi/In
iii) Value of Vm
= sf /2 = 75 / 2 = 37.5 mph
