Houses the CYLINDERS, Water Jacket & Crankcase
Answer:
the percent increase in the velocity of air is 25.65%
Explanation:
Hello!
The first thing we must consider to solve this problem is the continuity equation that states that the amount of mass flow that enters a system is the same as what should come out.
m1=m2
Now remember that mass flow is given by the product of density, cross-sectional area and velocity
(α1)(V1)(A1)=(α2)(V2)(A2)
where
α=density
V=velocity
A=area
Now we can assume that the input and output areas are equal
(α1)(V1)=(α2)(V2)
Now we can use the equation that defines the percentage of increase, in this case for speed
Now we use the equation obtained in the previous step, and replace values
the percent increase in the velocity of air is 25.65%
Answer:
A) Wet bulb temperature of #1 is less than that of #2
Explanation:
This can be gotten from pinpointing the states of the two containers on a psychometric chart.
Answer:
i) σ1 = 133.5 MPa
σ2 = -2427 MPa
ii) 78.89 MPa
Explanation:
Given data:
ε1 = 0.0020 and ε2 = –0.0010
E = 71 GPa
v = 0.35
<u>i) Determine the biaxial stresses σ1 and σ2 using the relations below</u>
ε1 = σ1 / E - v (σ2 / E) -----( 1 )
ε2 = σ2 / E - v (σ1 / E) -------( 2 )
resolving equations 1 and 2
σ1 = E / 1 - v^2 { ε1 + vε2 } ---- ( 3 )
σ2 = E / 1 - v^2 { ε2 + vε1 } ----- ( 4 )
input the given data into equation 3 and equation 4
σ1 = 133.5 MPa
σ2 = -2427 MPa
<u>ii) Calculate the value of the maximum shear stress ( Zmax )</u>
Zmax = ( σ1 - σ2 ) / 2
= 133.5 - ( - 2427 ) / 2
= 78.89 MPa
Answer: 0.306 kg/s
Explanation:
If we assume that the specific heat for all stream is constant, we can then say, the mass flow rate of cold water can be calculated by using the energy balance equation.
The energy balance equation basically states that, the heat gained is equal to the heat lost
m'1h1 + m'2h2 = m'3h3
m'1T1 + m'2T2 = (m'1 + m'2) T3
0.5 (60) + m'2(10) = (0.5 + m'2)41
30 + 10m'2 = 20.5 + 41m'2
30 - 20.5 = 41m'2 - 10m'2
9.5 = 31m'2
m'2 = 9.5 / 31
m'2 = 0.306 kg/s
