Answer:
22.90 × 10⁸ kg
Explanation:
Given:
Diameter, d = 0.02 m
ωₙ = 0.95 rad/sec
Time period, T = 0.35 sec
Now, we know
T= 
where, L is the length of the steel cable
g is the acceleration due to gravity
0.35= 
or
L = 0.0304 m
Now,
The stiffness, K is given as:
K = 
Where, A is the area
E is the elastic modulus of the steel = 2 × 10¹¹ N/m²
or
K = 
or
K = 20.66 × 10⁸ N
Also,
Natural frequency, ωₙ = 
or
mass, m = 
or
mass, m = 
mass, m = 22.90 × 10⁸ kg
The real answer - for 1- true
you have to pay attention in class to actually learn this subject if you want to work in this workforce
second - false
there is no way that the Elecrtomagnetic signal can just cause awful signal attenuation.
Answer:
Engineering aims to allow technical parts, structures and/or systems, such as those of a machine, to fulfill their function. To this end, occurring and/or desired processes (the operation thereof) are investigated and elaborated. Appropriate parts are designed individually or in a team, occurring stresses are calculated and the parts to be produced are modeled and/or specified on technical drawings. In some fields, maintenance is a standard part of the work to be performed. For a large part of engineering, standards and agreements have been drawn up with a view to the desired safety and practical applicability.
Answer:
The kinetic energy of the weight is 344.5 J
Explanation:
Given that:
Force = F = 65 newton
distance = d = 5.3 meters
We have to find change in kinetic energy ΔK.E
Now we know that, initially kinetic energy was 0 So the formula we use will be:
Work done = Change in kinetic energy
Mathematically,
W = ΔK.E
As we know W = F . d and ΔK.E = K.E(final) - K.E(initial)
So by putting values:
F . d = K.E(final) - K.E(initial)
F . d = K.E(final)
As K.E(initial) is 0 so by putting values of F and d
(65)* (5.3) = K.E(final)
344.5 J = K.E(final)
So the change in K.E will also be 344.5 J
i hope it will help you!
