Answer:
ΔT= 11.94 °C
Explanation:
Given that
mass of water = 10 kh
Time t= 15 min
Heat lot from water = 400 KJ
Heat input to the water = 1 KW
Heat input the water= 1 x 15 x 60
=900 KJ
By heat balancing
Heat supply - heat rejected = Heat gain by water
As we know that heat capacity of water


Now by putting the values
900 - 400 = 10 x 4.187 x ΔT
So rise in temperature of water ΔT= 11.94 °C
Answer:
a. 0.4544 N
b. 
Explanation:
For computing the normality and molarity of the acid solution first we need to do the following calculations
The balanced reaction



= 0.27264 g


= 0.006816 mol
Now
Moles of
needed is

= 0.003408 mol


= 0.333984 g
Now based on the above calculation
a. Normality of acid is


= 0.4544 N
b. And, the acid solution molarity is


= 0.00005112
=
We simply applied the above formulas
Answer: 
Explanation:
Given
Discharge is 
Diameter of pipe 
Distance between two ends of pipe 
friction factor 
Average velocity is given by

Pressure difference is given by

Answer:
Tension in cable BE= 196.2 N
Reactions A and D both are 73.575 N
Explanation:
The free body diagram is as attached sketch. At equilibrium, sum of forces along y axis will be 0 hence
hence

Therefore, tension in the cable, 
Taking moments about point A, with clockwise moments as positive while anticlockwise moments as negative then



Similarly,


Therefore, both reactions at A and D are 73.575 N
Answer:
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Explanation:
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