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victus00 [196]
4 years ago
13

A restaurant offers three vegetable side dishes, two fruit side dishes, and five grain-based side dishes. Each entree comes with

two side dishes.
What is the approximate probability of randomly choosing one vegetable and one grain-based side dish?
0.08889
0.17778
0.16667
0.33333
Mathematics
2 answers:
JulsSmile [24]4 years ago
8 0
The answer on E2020 is D: <span>0.33333</span>
In-s [12.5K]4 years ago
5 0

Answer: 0.33333

Step-by-step explanation:

Given: Number of Vegetable side dishes = 3

Number of Fruit side dishes = 2

Number of Grain-based side dishes = 5

Thus, the total number of side dishes =3+2+5=10

Now, the number of ways for choosing two side dishes from total 10 dishes will be :

^{10}C_2=\frac{10!}{(10-2)!2!=45}

Then the number of ways to randomly choose one vegetable and one grain-based side dish is given by :-

^{3}C_1\times^{5}C_1=3\times5=15

Thus, the probability of randomly choosing one vegetable and one grain-based side dish =\frac{15}{45}=\frac{1}{3}=0.33333333...\approx0.33333

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