Ask question

Ask question

All categories

3 years ago

13

7.1-x=4.9? Need help

2 answers:

Novosadov [1.4K]3 years ago

8 0

Let's solve your equation step-by-step.
7.1
−
x
=
4.9
Step 1: Simplify both sides of the equation.
7.1
−
x
=
4.9
7.1
+
−
x
=
4.9
−
x
+
7.1
=
4.9
Step 2: Subtract 7.1 from both sides.
−
x
+
7.1
−
7.1
=
4.9
−
7.1
−
x
=
−
2.2
Step 3: Divide both sides by -1.
−
x
−
1
=
−
2.2
−
1
x
=
2.2

Novosadov [1.4K]3 years ago

6 0

Answer:

Take 7.1-4.9=x

Step-by-step explanation:

You might be interested in

8a-9÷3 if a=7/8<br> its algebra i need help

uysha [10]

Answer:

4

Step-by-step explanation:

Plug 7/8 into a.

8(7/8)-9/3 Multiply.

7-9/3 Divide.

7-3 Subtract.

4

Hope this helps!! Have a great day! (｡･∀･)ﾉﾞ

4 0

3 years ago

Please help me solve this problem ASAP

DiKsa [7]

$\bold{\huge{\blue{\underline{ Solution }}}}$

<h3><u>Given </u><u>:</u><u>-</u></h3>

<u>The </u><u>right </u><u>angled </u><u>below </u><u>is </u><u>formed </u><u>by </u><u>3</u><u> </u><u>squares </u><u>A</u><u>, </u><u> </u><u>B </u><u>and </u><u>C</u>
<u>The </u><u>area </u><u>of </u><u>square </u><u>B</u><u> </u><u>has </u><u>an </u><u>area </u><u>of </u><u>1</u><u>4</u><u>4</u><u> </u><u>inches </u><u>²</u>
<u>The </u><u>area </u><u>of </u><u>square </u><u>C </u><u>has </u><u>an </u><u>of </u><u>1</u><u>6</u><u>9</u><u> </u><u>inches </u><u>²</u>

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>area </u><u>of </u><u>square </u><u>A</u><u>? </u>

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u><u> </u></h3>

The right angled triangle is formed by 3 squares

<u>We </u><u>have</u><u>, </u>

Area of square B is 144 inches²
Area of square C is 169 inches²

<u>We </u><u>know </u><u>that</u><u>, </u>

$\bold{ Area \: of \: square = Side × Side }$

Let the side of square B be x

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

$\sf{ 144 = x × x }$

$\sf{ 144 = x² }$

$\sf{ x = √144}$

$\bold{\red{ x = 12\: inches }}$

Thus, The dimension of square B is 12 inches

<h3><u>Now, </u></h3>

Area of square C = 169 inches

Let the side of square C be y

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

$\sf{ 169 = y × y }$

$\sf{ 169 = y² }$

$\sf{ y = √169}$

$\bold{\green{ y = 13\: inches }}$

Thus, The dimension of square C is 13 inches.

<h3><u>Now, </u></h3>

It is mentioned in the question that, the right angled triangle is formed by 3 squares

The dimensions of square be is x and y

Let the dimensions of square A be z

<h3><u>Therefore</u><u>, </u><u>By </u><u>using </u><u>Pythagoras </u><u>theorem</u><u>, </u></h3>

<u>The </u><u>sum </u><u>of </u><u>squares </u><u>of </u><u>base </u><u>and </u><u>perpendicular </u><u>height </u><u>equal </u><u>to </u><u>the </u><u>square </u><u>of </u><u>hypotenuse </u>

<u>That </u><u>is</u><u>, </u>

$\bold{\pink{ (Perpendicular)² + (Base)² = (Hypotenuse)² }}$

<u>Here</u><u>, </u>

Base = x = 12 inches
Perpendicular = z
Hypotenuse = y = 13 inches

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

$\sf{ (z)² + (x)² = (y)² }$

$\sf{ (z)² + (12)² = (169)² }$

$\sf{ (z)² + 144 = 169}$

$\sf{ (z)² = 169 - 144 }$

$\sf{ (z)² = 25}$

$\bold{\blue{ z = 5 }}$

Thus, The dimensions of square A is 5 inches

<h3><u>Therefore</u><u>,</u></h3>

Area of square

$\sf{ = Side × Side }$

$\sf{ = 5 × 5 }$

$\bold{\orange{ = 25\: inches }}$

Hence, The area of square A is 25 inches.

6 0

3 years ago

Which relationship is an example of a proportional relationship?<br> helppp?

andreev551 [17]

Answer: “samuel earns $20 for each lawn he mows”

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Evaluate C= 2 xr, for r=8.<br> C= 100<br> OC= 16<br> OC= 287<br> C= 16

____ [38]

C= 2 x r where r = 8
C = 2 x 8
C = 16.
Hope I helped:)

3 0

4 years ago

How can the figure below be changed so that the diagonals form two lines of symmetry?

Ganezh [65]

Moving point c one unit to the left

8 0

3 years ago

Read 2 more answers