Answer:nswer. Since there are 16 bytes in a cache block, the OFFSET field must contain 4 bits (24 = 16). To determine the number of bits in the SET field, we need to determine the number of sets. Each set contains 2 cache blocks (2-way associative) so a set contains 32 bytes.
Explanation:
Answer:
Prejudice can be either positive or negative.
Answer:
void mn(int m, int n){
int sum = 0;
int count = 0;
if(m<n){
for(int i = m;i<=n;i++){
sum+=i;
}
}
else{
for(int i = n;i<=m;i++){
sum+=i;
}
}
count = abs(m - n)+1;
cout<<"Sum: "<<sum<<endl;
cout<<"Average: "<<(float)sum/count;
}
Explanation:
This line defines the method
void mn(int m, int n){
This initializes sum and count to 0
int sum = 0;
int count = 0;
This checks if m is less than n
if(m<n){
This iterates from m to n and calculates the sum of numbers between this interval
<em> for(int i = m;i<=n;i++){</em>
<em> sum+=i;</em>
<em> }</em>
<em> }</em>
If otherwise,
else{
This iterates from n to m and calculates the sum of numbers between this interval
<em> for(int i = n;i<=m;i++){</em>
<em> sum+=i;</em>
<em> }</em>
<em> }</em>
This calculates the range from m to n using absolute function
count = abs(m - n)+1;
This prints the calculated sum
cout<<"Sum: "<<sum<<endl;
This calculates and prints the average
cout<<"Average: "<<(float)sum/count;
}
<em>See attachment for complete program that includes the main (in c++)</em>
