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olya-2409 [2.1K]
3 years ago
7

AB is tangent to circle O at B. Find the length of the radius r for AB = 9 and AO = 10.5. Round to the nearest tenth if necessar

y. The diagram is not to scale.

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
4 0

Answer:

5.4

Step-by-step explanation:

At the point of tangency, the degree measure is 90. Hence Angle ABO is 90 degrees. So triangle ABO is right triangle.

In a right triangle, we can use the pythagorean theorem, which says:

Leg1^2 + Leg2^2 = Hypotenuse^2

Where

Leg 1 and Leg 2 are 2 sides of the triangle, respectively, and

hypotenuse is the side "opposite" of the 90 degree angle

In this diagram, thus we can write:

r^2 + AB^2 = AO^2

Now putting the information we know, we can solve for r:

r^2 + 9^2 = (10.5)^2

r^2 + 81 = 110.25

r^2 = 110.25 - 81

r^2 = 29.25

r = Sqrt(29.25)

r = 5.41

Rounded to nearest tenth, it is 5.4, 2nd answer chice is right.

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In the circle, m arc BC = 72°. The diagram is not drawn to scale. <br><br>What is m angle BCP
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Answer:

Measure of ∠BCP is 36°

Step-by-step explanation:

Given the circle in which measure of arc BC is 72°

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By theorem angle subtended at the centre is twice the angle formed at the circumference of circle.

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Option D is correct

   

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Step-by-step explanation:

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Step-by-step explanation:

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