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max2010maxim [7]
3 years ago
6

The perimeter of a rectangle is 26 meters. The difference between the length and the width is 5 meters. Find the width

Mathematics
1 answer:
Scilla [17]3 years ago
3 0
Try making a substitution:
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What's 30.08 divided by 4
belka [17]
30.08 divided by 4 is 7.52
6 0
3 years ago
Read 2 more answers
Okay it might be simple but can yall help and give me a real answer plz UwU
ad-work [718]

Answer:

6 cubic cm

Step-by-step explanation:

3 · 3 · 2 = 18

18 · 1/3 = 6

7 0
3 years ago
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Please simplify this please it’s due really soon!
iren2701 [21]

Step-by-step explanation:

\frac{ {13}^{6}  \div  {13}^{8}  \times  {13}^{ - 4} }{ {13}^{ - 2} }

You need to remember the properties of exponents: multiplication adds the exponents, division subtracts the exponents.

If you multiply two powers with the same base, the result will be the base to the sum of the powers.

If you divide two powers with the same base, the result will be the base to the difference of the powers.

In your case you will this:

{13}^{6 - 8 + ( - 4) - ( - 2)}

That is:

{13}^{ - 4}

Or:

\frac{1}{ {13}^{4} }

7 0
3 years ago
The base of the pyramid is a square what is the surface area if the pyramids height is 4 feet in the area of the base is 36 ft.?
KATRIN_1 [288]

Answer:

96 ft²

Step-by-step explanation:

The general formula for the surface area of a pyramid is:  

SA = \frac{1}{2}pl + B, were p = the perimeter of the base, l = the slant height and B = the area of the base

Since the area of the base is 36 ft², then each side is √36, or 6 ft. The perimeter is the sum of all the sides, so 6 x 4 = 24 ft.

Given the overall height of the pyramid is 4 feet, you can use the Pythagorean Theorem (a² + b² = c²) to find the slant height (hypotenuse) of the pyramid.  Using 3 feet for 'a' and 4 feet for 'b':

3² + 4² = c² or 9 + 16 = 25

25 = c² or c = 5

SA =  \frac{1}{2}(24)(5) + 36

SA = 60 + 36 = 96 ft²

8 0
3 years ago
6.
Ilia_Sergeevich [38]

Answer:

  • A. 5 to the power of negative 5 over 6

Step-by-step explanation:

  • \sqrt[3]{5} \sqrt{5} /\sqrt[3]{5^5} =
  • 5^{1/3+1/2-5/3}=
  • 5^{1/2-4/3}=
  • 5^{3/6-8/6}=
  • 5^{-5/6}
6 0
2 years ago
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