All categories

3 years ago

What the nearest hundred thousand for 767074

Mathematics

1 answer:

Law Incorporation [45]3 years ago

5 0

7 is digit for hundred thousands and 6 is for ten thousands so the answer is 800,000

You might be interested in

What is the reciprocal of 3^-2 ?

weqwewe [10]

Answer:

1/3^2

Im trying to earn my brainliest..so if you don't mind :)

8 0

3 years ago

The expresion 14.42d + 12.24c can be used to find the total cost of d punds of almonds and c pounds of cashews how much does it

madam [21]

Answer:

Therefore the total cost of $3\frac{1}{2}$ pound of almonds and $3\frac{1}{2}$ pound of cashews is

$y=\frac{36.05}{d}+\frac{30.6}{c}$

[Where y is in $]

Step-by-step explanation:

[The unit of price is not given, I assume the unit of cost as $]

Given expression is 14.42 d + 12.24 c .

Where the amount of almond is denoted by d pounds.

and the amount of cashews is denoted by c pounds.

The cost price of d pound of almond is $14.42.

The cost price of 1 pound of almond is $\$\frac{14.42}{d}$

Then the cost of $3\frac{1}{2}$ pound of almond is $=\$\frac{ 14.42 \times3 \frac{1}{2} }{d}$

$=\$\frac{36.05}{d}$

Again from the given expression we get that,

The cost price of c pound of cashews is $12.24

The cost price of 1 pound of cashews is $=\$\frac{12.24}{c}$

Then the cost of $3\frac{1}{2}$ pound of cashews is $=\$\frac{ 12.24 \times3 \frac{1}{2} }{c}$

$=\$\frac{30.6}{c}$

Therefore the total cost of $3\frac{1}{2}$ pound of almonds and $3\frac{1}{2}$ pound of cashews is

y = $=\frac{36.05}{d}+\frac{30.6}{c}$

[Where y is in$]

7 0

3 years ago

Can somebody help me on this problem please I will give you brainliest:)

vodka [1.7K]

That’s confusing do you know the formula your supposed to use?

5 0

3 years ago

the ideal width of a safety belt strap for a certain automobile is 6 cm and actual width can vary by 0.4 CM write an absolute va

jeyben [28]

Heyyyyy
Hope this helps!
~Nadia~

3 0

3 years ago

21 22 23 24 25 TIME REMAINING 01:40:27 A hat contains slips of paper with the names of the 26 other students in Eduardo’s class

Pani-rosa [81]

There are 26 - 10 = 16 girls. The number of ways to choose 2 girls from a set of 16 is C(16, 2) = 120. (Your class might be using a different notation for combinations, like $_{16}C_2$ .)

The number of ways to choose 2 people (boys or girls) from a set of 26 is C(26, 2) = 325.

The probability of choosing 2 girls is $\frac{120}{325} = \frac{24}{65}$

Example: how to compute C(16,2):

$C(n, r) = \frac{n!}{r!(n-r)!} \\ C(16, 2) = \frac{16!}{2!(16-2)!} \\ =\frac{16!}{2! \times 14!} \\ =\frac{16\times 15}{2\times 1} \\ =120$

7 0

4 years ago