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wlad13 [49]
3 years ago
10

Would each of them be able to be the side lengths of a triangle?

Mathematics
2 answers:
ratelena [41]3 years ago
8 0
Pythagoras Theorem:
hipotenuse²=leg₁²+leg₂²

First posible triangle:
hypotenuse=13    (13²=169)
leg₁=12                ( 12²=144)
leg₂=5                  (5²=25)

13³=144 + 25


Answer:can be side lengths of a triangle

Second triangle:
 hypotenuse=12.6    (12.6²=158.76)
leg₁=6.7                ( 6.7²=44.89)
leg₂=6.5                  (6.5²=42.25)

leg₁²+leg₂²=44.89+42.25=87.14≠158.76

Answer: cannot be side lenghts of a triangle.

third triangle:
hypotenuse=13    (13²=169)
leg₁=12                ( 12²=144)
leg₂=11                  (11²=121)

leg₁²+leg₂²=144+121=265≠169

Answer: cannot be side lenghts of a triangle.

fourth triangle:
hypotenuse=13   (13²=169)
leg₁=6                ( 6²=36)
leg₂=4                  (4²=16)

leg₁²+leg₁²=36+16=52≠169

Answer: cannot be side lenghts of a triangle.
Mariulka [41]3 years ago
8 0
Use a bit of logic

the longest side of a triangle has to be less than the sum of the legnths of the other two sides (or else they won't connect or you get a striahge line or something)
baseically
longestside<otherside+shortestside


12,13,5
13<12+5 is that true?
13<17
true
it can be a triangle


6.7,6.5,12.6
12.6<6.7+6.5
12.6<13.2
true, can be a triangle

13,12,11
13<12+11
13<23
true
can be a triangle

13,4,6
13<4+6
13<10
false, cannot be a triangle



all of them can be legnths of a triangle except last one
 
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4 years ago
Enter the ordered pair for the vertices for 180°,0)(QRST).
goldfiish [28.3K]

Answer:

The ordered pair for the vertices for r₍₁₈₀ ₀₎(QRST), is given as follows;

Q' = (-1, -3) R' = (-3, 3) S' = (0, 2) T' = (2, -1)

Step-by-step explanation:

The coordinates of he vertices of the triangle QRST are;

Q(1, 3), R(3, -3), S(0, -2), T(-2, 1)

A rotation of a point with coordinates (x, y) 180° about the origin gives;

The coordinate of the point of the preimage before the rotation = (x, y)

The coordinate of the point of the image after the rotation = (-x, -y)

Therefore we have;

The image of point Q(1, 3) after 180° rotation = Q'(-1, -3)

The image of point R(3, -3) after 180° rotation = R'(-3, 3)

The image of point S(0, -2) after 180° rotation = S'(0, 2)

The image of point T(-2, 1) after 180° rotation = T'(2, -1)

The ordered pair for the vertices for r₍₁₈₀ ₀₎(QRST), is therefore, Q'(-1, -3), R'(-3, 3), S'(0, 2), and T'(2, -1);

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6 0
3 years ago
ε = {x: 2 ≤ x ≤30, x is an integer}, M = {even numbers}, P = {prime numbers}, T = {odd numbers} Find: M-T
german

Answer:

M-T={even numbers}

Step-by-step explanation:

We are given that

\varepsilon={x:2\leq x\leq 30,x is an integer}

M={even numbers}

P={Prime numbers}

T={odd  numbers}

We have to find M-T

M\cap T=\phi

We know that

A-B=A-A\cap B

Using the formula

Then, we get

M-T=M-M\cap T

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5 0
3 years ago
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tamaranim1 [39]
Hey there!

To find the markup percentage, you must use your formula for percent markup:
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Because your profit is found by subtracting 13-10, 3, your profit would be 3. You also know that your cost is 10.

Now, plug in your values:
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Therefore, your percent markup would be about 30%.

Hope this helps and have a nice day!
5 0
4 years ago
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