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pantera1 [17]
3 years ago
14

(4x – 6°) (x + 6y)" Solve for y.

Mathematics
1 answer:
12345 [234]3 years ago
4 0

Answer:

Simplifying

(4x + -6) = (x + 6y)

Reorder the terms:

(-6 + 4x) = (x + 6y)

Remove parenthesis around (-6 + 4x)

-6 + 4x = (x + 6y)

Remove parenthesis around (x + 6y)

-6 + 4x = x + 6y

Solving

-6 + 4x = x + 6y

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1x' to each side of the equation.

-6 + 4x + -1x = x + -1x + 6y

Combine like terms: 4x + -1x = 3x

-6 + 3x = x + -1x + 6y

Combine like terms: x + -1x = 0

-6 + 3x = 0 + 6y

-6 + 3x = 6y

Add '6' to each side of the equation.

-6 + 6 + 3x = 6 + 6y

Combine like terms: -6 + 6 = 0

0 + 3x = 6 + 6y

3x = 6 + 6y

Divide each side by '3'.

x = 2 + 2y

Simplifying

x = 2 + 2y

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At 106°F, a certain insect chirps at a rate of 67 times per minute, and at 108°F, they chirp 83 times per minute. Write an equat
Step2247 [10]

Answer:

y=8x-781

Here, x represents temperature and y denotes rate of chirping per minute.

Step-by-step explanation:

Let x represents temperature and y denotes rate of chirping per minute.

At 106°F, a certain insect chirps at a rate of 67 times per minute.

Take (x_1,y_1)=(106,67)

At 108°F, they chirp 83 times per minute.

Take (x_2,y_2)=(108,83)

Slope intercept form:

y-y_1=(\frac{y_2-y_1}{x_2-x_1})(x-x_1)

y-67=(\frac{83-67}{108-106})(x-106)\\\\y-67=(\frac{83-67}{108-106})(x-106)\\\\y-67=(\frac{16}{2})(x-106)\\\\y-67=8(x-106)\\y-67=8x-848\\y=8x+67-848\\y=8x-781

3 0
3 years ago
5.8 times 10 and show work (optional)
Step2247 [10]

Answer:

58

Step-by-step explanation:

A easy way to get this is to remove the decimal in 5.8 which gives you ----> 58

NOTE: This works for any problem multiplying 10 x a decimal.

7 0
3 years ago
HELP PLEASE ! ASAP !
Blizzard [7]

Answer: i think 23x

Step-by-step explanation: i might be incorrect

4 0
3 years ago
Read 2 more answers
Find the distance between the points L(7,-1) and M(-2, 4).
zysi [14]

Answer:

The answer is

\sqrt{106}  \:  \:  \: or \:  \:  \: 10.3 \:  \:  \:  \: units

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  } \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

L(7,-1) and M(-2, 4)

The distance between them is

|LM|  =   \sqrt{ ({7 + 2})^{2}  + ( { - 1 - 4})^{2} }  \\  =  \sqrt{ {9}^{2}  +  ({ - 5})^{2} }  \\  =  \sqrt{81 + 25}  \\  =  \sqrt{106}  \:  \:  \:  \:  \:  \:  \:  \\  = 10.29563014...

We have the final answer as

\sqrt{106}  \:  \:  \: or \:  \:  \: 10.3 \:  \:  \:  \: units

Hope this helps you

4 0
3 years ago
Linear relationships? Would it be B?
mart [117]
It would be C 
hope it helped 




3 0
3 years ago
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