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Bezzdna [24]
3 years ago
5

A student places four identical cells into four different liquids. Cell Description of Liquid W Saltier than the cell X Less sal

ty than the cell Y Equally as salty as the cell Z Pure water with no salts Over time, which cell will look the smallest? Cell W cell X cell Y cell Z
Physics
2 answers:
Tems11 [23]3 years ago
8 0

This description can be expressed as follows:

Y>W>X

And,

W=Z


From these expressions we are able to find out that t<u>he saltiest cell description is Y</u>, <u>while the less salty is X</u>.

Now, salt is well known as a dehydrating agent. In a process called <u><em>osmosis</em></u> cells placed in a salty liquid environment lose water, how?

Well, cells have a semipermeable membrane, in which some substances can get inside. Cells also have water inside. <u>If a cell is placed in a quite salty liquid environment, salt will make the water inside the cells to come out,</u> drying the cell and diminishing its size.

So, in this case, according to the expressions above, Cell Y will look the smallest, while cell X will look the biggest.


If we pour pure water in each liquid, the salt concentration will change and each cell will begin to grow bigger, but the saltiest cell will still be smaller than the others with less salt concentration.

Finally, to answer the question: Y cell will look the smallest after this process.


Ann [662]3 years ago
8 0

Just look at the bottom of the first answer.

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Two balls with masses of 2.0 kg and 6.0 kg travel toward each other at speeds of 12 m/s and 4.0 m/s, respectively. If the balls
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The kinetic energy lost in the collision is 48 J

Explanation:

Given;

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mass of the second ball, m₂ = 6.0 kg

initial speed of the first ball, u₁ = 12 m/s

initial speed of the second ball, u₂ = 4 m/s

let v be the final velocity of the two balls after the inelastic collision

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

2 x 12 + 6 x 4 = v(2 + 6)

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48 / 8 = v

v = 6 m/s

The initial kinetic energy of the balls is calculated as;

K.E₁ = ¹/₂m₁u₁² + ¹/₂m₂u₂²

K.E₁ = ¹/₂(2)(12²) + ¹/₂(6)(4)²

K.E₁ = 144 + 48

K.E₁ = 192 J

The final kinetic of the balls is calculated as;

K.E₂ = ¹/₂(m₁ + m₂)(v²)

K.E₂ = ¹/₂(2 + 6)(6²)

K.E₂ = ¹/₂(8)(6²)

K.E₂ = 144 J

The lost in kinetic energy of the balls is K.E₂ - K.E₁ = 144 J - 192 J = -48 J

Therefore, the kinetic energy lost in the collision is 48 J

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The equation for the work-energy theorem can be computed as:

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From the above equation, let make speed(v) the subject of the formula:

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