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Elena-2011 [213]
3 years ago
9

What is the acceleration of an arrow that has a mass of 0.1 kg and a force of 9 N?

Physics
1 answer:
djverab [1.8K]3 years ago
4 0

Force = Mass x Acceleration

9N = 0.1kg x Acceleration

Acceleration = 9N / 0.1kg

Acceleration = 90 m/s^2

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A 2kg block has 70J of KE. It then travels 1.5 meters up a hill. As it travels up the hill friction does -12J of work on the blo
Dima020 [189]

Answer:

v = 5.34[m/s]

Explanation:

In order to solve this problem, we must use the theorem of work and energy conservation. This theorem tells us that the sum of the mechanical energy in the initial state plus the work on or performed by a body must be equal to the mechanical energy in the final state.

Mechanical energy is defined as the sum of energies, kinetic, potential, and elastic.

E₁ = mechanical energy at initial state [J]

E_{1}=E_{pot}+E_{kin}+E_{elas}\\

In the initial state, we only have kinetic energy, potential energy is not had since the reference point is taken below 1.5[m], and the reference point is taken as potential energy equal to zero.

In the final state, you have kinetic energy and potential since the car has climbed 1.5[m] of the hill. Elastic energy is not available since there are no springs.

E₂ = mechanical energy at final state [J]

E_{2}=E_{kin}+E_{pot}

Now we can use the first statement to get the first equation:

E_{1}+W_{1-2}=E_{2}

where:

W₁₋₂ = work from the state 1 to 2.

E_{k}=\frac{1}{2} *m*v^{2} \\

E_{pot}=m*g*h

where:

h = elevation = 1.5 [m]

g = gravity acceleration = 9.81 [m/s²]

70 - 12 = \frac{1}{2}*2*v^{2}+2*9.81*1.5

58 = v^{2} +29.43\\v^{2} =28.57\\v=\sqrt{28.57}\\v=5.34[m/s]

4 0
3 years ago
Two forces act on an object. One force has a magnitude of 10 N directed north, and the other force has a magnitude of 2 N direct
xeze [42]

Answer:

8 N North.

Explanation:

Given that,

One force has a magnitude of 10 N directed north, and the other force has a magnitude of 2 N directed south.

We need to find the magnitude of net force acting on the object.

Let North is positive and South is negative.

Net force,

F = 10 N +(-2 N)

= 8 N

So, the magnitude of net force on the object is 8 N and it is in North direction (as it is positive). Hence, the correct option is (d) "8N north".

7 0
3 years ago
The four main elements in food that help energy to move from one trophic level to another are _____.
PolarNik [594]
I think these may help. protein, calcium
7 0
3 years ago
Which factor affects the angle of sunlight on Earth? The distance between Earth and the sun Earth's tilt from its axis The path
Rainbow [258]
Earth’s tilt from its axis.
For explanation:
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6 0
1 year ago
A mechanic uses a jack to lift up a car. He exerts a force of 11,000 N at a distance of 3m from the axis of rotation. How much t
pshichka [43]

Answer:

<h2>The amount of torque put on the car is 33,000Nm</h2>

Explanation:

Formula for calculating torque is expressed as T = rFsin\theta\\ where;

r is the radius of the  of the arm of the jack = 3m

F is the force exerted = 11000

\theta\\ is the angle of rotation = 90°

On substituting;

T = 3*11000sin90^{o} \\T = 3*11000 (sin90^{o} =1)\\T = 33000Nm

6 0
3 years ago
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