A certain copper wire has a resistance of 10.5 Ω. It is cut into two pieces such that one piece has 6.0 times the resistance of
the other. Determine the resistance of each piece.
1 answer:
Answer:
1.5 ohm, 9 ohm
Explanation:
Total resistance, R = 10.5 ohm
Let the resistance of one piece is r and then the resistance of another piece is 10.5 - r.
According to question, the resistance of one piece is equal to the 6 times the resistance of another piece.
so, 6 r = 10.5 - r
7 r = 10.5
r = 1.5 ohm
Thus, the resistance of one piece is 1.5 ohm and resistance of another piece is 10.5 - 1.5 = 9 ohm.
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paraan ito ng pagrerespeto
Weight tending to shear the pin is
W = 24.0 N
The shear area of the pin is
A = (π/4)*(2.0 x 10⁻³ m)² = 3.1416 x 10⁻⁶ m².
The shear stress is
τ = (24.0 N)/(3.1416 x 10⁻⁶ m²)
= 7.64 x 10⁶ Pa
= 7.64 MPa
Answer: 7.64 Mpa
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Answer is C.
