Answer:
Explanation:
Given
Em wave is in the form of
where
Wave constant for EM wave k is
Wavelength of wave
A certain copper wire has a resistance of 10.5 Ω. It is cut into two pieces such that one piece has 6.0 times the resistance of
1 answer:
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Answer:
641 nm.
Explanation:
Given that,
A transmission grating has 5200 slits/cm.
We need to find the longest wavelength that can be observed in the third order. Using grating equation as follows :
...(1)
d is slit spacing
No fo slit per unit length :
We know that, N = 1/d
For longest wavelength, θ = 90°
From equation (1)
Hence, the longest wavelength in third order for a transmission grating is 641 nm.
Answer:
option (c)
Explanation:
Fundamental frequency of segment A = f
Second harmonic frequency of B = fundamental frequency of A .
Tension in both the wires is same and the mass density is also same as the wires are identical.
fundamental frequency of wire A is given by
.... (1)
Second harmonic of B is given by
.... (2)
Equation (1) is equal to equation (2), we get
So, LB = 2 L
Thus, the length of wire segment B is 2 times the length of wire segment A.