All categories

3 years ago

What must gymnasts begin to train at a very early age

Physics

1 answer:

Vladimir [108]3 years ago

3 0

How to stretch your muscles so you don't tear one

You might be interested in

Does a shadow have a shadow

Aleks04 [339]

Herrrrrrreeeee yoouuuuu gooooo

8 0

3 years ago

What is the way that you can make wishes for others come true?

icang [17]

Answer:

If you want people to grant your wishes dream it or try to make they feel bad for you or buy them something back you can mostly get what they want

Explanation:

They will give what you want back cause some people like giving people gifts back

4 0

3 years ago

Read 2 more answers

If you have 3 equal plates hanging 2 spaces from the center of a balance, at what distance would you need to place 2 equal plate

Reptile [31]

You answere would be C. 3 spaces

3 0

3 years ago

Hurricanes are especially destructive because of the abrupt decrease in air pressure that they bring with the winds. Consider a

ivann1987 [24]

Answer:

2.96 × 10^4 N

Explanation:

1 atm = 101325 N/m², pressure inside the airtight room = 1.02 atm, pressure outside due to hurricane = 0.91 atm

net pressure directed outward = P inside - P outside

net pressure = 1.02 - 0.91 = 0.11 atm

where 1 atm = 101325N/m²

0.11 atm = 0.11 × 101325 N/m² = 11145.75 N/m²

area of the square wall = l × l where l is the length of the wall in meters = 1.63 × 1.63 = 2.6569

net pressure = net force / area

make net force subject of the formula

net force = net pressure × area = 11145.75 × 2.6569 = 2.96 × 10 ^4 N

8 0

3 years ago

A 3.49 rad/s (33 1/3 rpm) record has a 4.00 kHz tone cut in the groove. If the groove is located d = 0.080 m from the center of

lubasha [3.4K]

Answer:

$v = \lambda f$ (1)

And we have this other relationship between the linear speed and the angular speed:

$v = rw$ (2)

We can find the linear velocity like this:

$v = 0.08 m * 3.49 \frac{rad}{s}= 0.279 m/s$

And then from equation (1) we can solve for the frequency and we got:

$\lambda = \frac{v}{f}$

And replacing we got:

$\lambda = \frac{0.279 m/s}{4000 Hz}= 6.98x10^{-5} m$

And that represent the wavelength in th groove for this case.

Explanation:

For this case we have the following data given:

$w = 3.49 rad/s$ represent the angular velocity

$f = 4 kHz *\frac{1000 Hz}{1 kHz}= 4000 Hz$ represent the frequency

$r = 0.08 m$ we assume that this respresent the distance from the center

We know the following relationship between the wavelength $\lambda$ and the velocity of a wave:

$v = \lambda f$ (1)

And we have this other relationship between the linear speed and the angular speed:

$v = rw$ (2)

We can find the linear velocity like this:

$v = 0.08 m * 3.49 \frac{rad}{s}= 0.279 m/s$

And then from equation (1) we can solve for the frequency and we got:

$\lambda = \frac{v}{f}$

And replacing we got:

$\lambda = \frac{0.279 m/s}{4000 Hz}= 6.98x10^{-5} m$

And that represent the wavelength in th groove for this case.

7 0

3 years ago