Answer:
The length of the rectangle 'l' = 20
The width of the rectangle 'w' = 14
Step-by-step explanation:
<u>Explanation</u>:-
Let 'x' be the width
Given data the length of a rectangular patio is 8 feet less than twice its width
2x-8 = length
The area of rectangle = length X width
Given area of rectangle = 280 square feet
x(2x-8) = 280
2(x)(x-4) =280
x(x-4) =140
x^2 -4x -140=0
x^2-14x+10x-140=0
x(x-14)+10(x-14)=0
(x+10)(x-14) =0
x = -10 and x = 14
we can choose only x =14
The width of the rectangle 14
The length of the rectangle 2x-8 = 2(14)-8 = 28 -8 =20
The length of the rectangle 'l' = 20
The width of the rectangle 'w' = 14
This is not my level but i can try to solve it
Answer:
Initial equation: 5x + 2 = 3x + 12
x = 5
Step-by-step explanation:
Point C is the midpoint between A and B.
This means that:
AC = CB
We have that:
AC = 5x + 2
CB = 3x + 12
Since AC = CB, the initial equation is:
5x + 2 = 3x + 12
Now we can solve
5x + 2 = 3x + 12
5x - 3x = 12 - 2
2x = 10
x = 10/2
x = 5
