We may answer the question above by substituting the values of the coordinates of the points in the choices to the x and y of the inequality.
A. (-2, 4) 4 - 4(-2) ≤ -6 12 ≤ -6 FALSE
B. (1, -2) -2 - 4(1<span>) ≤ -6 -6 ≤ -6 TRUE
C (1, 3) 3</span> - 4(1<span>) ≤ -6 -1 ≤ -6 FALSE
D. (2, 3) 3</span> - 4(2<span>) ≤ -6 -5 ≤ -6 FALSE
The answer would be letter B. </span>
Answer:
2/3
Step-by-step explanation:
log27(9)
Factor the number: 27=3³
= log3³(9)
Apply log rule: loga^b(x) - 1/b loga(x).
log3³(9) =1/3 log3³(9)
=1/3 log3³(9)
Factor the number: 9=3²
=1/3 log3³(3²)
Apply log rule: loga(a^b) =b
log3 (3²) =2
1/3×2
=2/3
Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:

The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:
X = 590:


Z = 0.76
Z = 0.76 has a p-value of 0.7764.
X = 400:


Z = -0.89
Z = -0.89 has a p-value of 0.1867.
0.7764 - 0.1867 = 0.5897 = 58.97%.
58.97% of students would be expected to score between 400 and 590.
More can be learned about the normal distribution at brainly.com/question/27643290
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Answer:
I think the answer is m= -91