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3 years ago

13

A lighting products company has put a new brand of solar lightbulbs on the market. The graph shows the estimated revenue, in mil

lions of dollars, as the selling price of the lightbulb varies. What selling price is expected to produce the maximum revenue? A. $2 B. $8 C. $5 D. $3

2 answers:

NeTakaya3 years ago

8 0

Answer:

the answer is 5$

Step-by-step explanation:

Mice21 [21]3 years ago

7 0

Answer:

$5

Step-by-step explanation:

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Mr. Claussen needs a total of 15 pounds of ground beef to make hamburgers for a company picnic. He finds that 2 pounds of ground

Marat540 [252]

Answer: $33.00

Step-by-step explanation:

Given

Mr. Claussen needs 15 Pounds of ground beef

It is stated that 2 pounds of beef cost $4.40

Using unitary method

1 Pound cost $\frac{4.4}{2}=\$2.2$

For 15 pounds it is

$\Rightarrow 15\times 2.2=\$33$

Thus, he has to spend $33 for 15 pound meat

6 0

2 years ago

What’s the answer to this equation?

Tresset [83]

Answer:

Part A) The graph in the attached figure

Part B) see the explanation

Step-by-step explanation:

Part A) Graph the function

we have the quadratic function

$y=3x^2-12x-36$

This is a vertical parabola open upward

The vertex is a minimum

using a graphing tool

The graph in the attached figure

Part B) What are the values of a, b and c?

we know that

The values of a and b represent the x-intercepts of the quadratic equation

The x-intercepts are

(-2,0) and (6,0)

so

$a=-2\\b=6$

Find the value of c

we know that

The x-coordinate of the vertex in a vertical parabola is equal to the midpoint of the roots

so

The value of c is equal to

$c=\frac{a+b}{2}$

substitute the given values

$c=\frac{-2+6}{2}=2$

see the attached figure

7 0

2 years ago

If x = a cosθ and y = b sinθ , find second derivative

Olin [163]

I'm guessing the second derivative is for <em>y</em> with respect to <em>x</em>, i.e.

$\dfrac{\mathrm d^2y}{\mathrm dx^2}$

Compute the first derivative. By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}$

We have

$y=b\sin\theta\implies\dfrac{\mathrm dy}{\mathrm d\theta}=b\cos\theta$

$x=a\cos\theta\implies\dfrac{\mathrm dx}{\mathrm d\theta}=-a\sin\theta$

and so

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{b\cos\theta}{-a\sin\theta}=-\dfrac ba\cot\theta$

Now compute the second derivative. Notice that $\frac{\mathrm dy}{\mathrm dx}$ is a function of $\theta$ ; so denote it by $f(\theta)$ . Then

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm dx}$

By the chain rule,

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm df}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}$

We have

$f=-\dfrac ba\cot\theta\implies\dfrac{\mathrm df}{\mathrm d\theta}=\dfrac ba\csc^2\theta$

and so the second derivative is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\frac ba\csc^2\theta}{-a\sin\theta}=-\dfrac b{a^2}\csc^3\theta$

4 0

3 years ago

FG is the midsegment of isosceles ABC, and is the midsegment of trapezoid CDEF. Segments EF, KM and DC are parallel. Find the m

Readme [11.4K]

BC=60 cm because FG is the midsegment of triangle ABC so it separates the sides of the triangle into two equal segments and 30(2)=60.
GF=22 cm because according to the Triangle Midsegment Theorem, GF=1/2(AC). GF=1/2(44 cm). GF=22 cm. Next, we can conclude EG and DA are 22 cm because the diagram marks them as congruent. So CD=44 cm+22 cm=66 cm. Then, we find that EF=EG+GF=22 cm+22 cm=44 cm. So, using the Trapezoid Midsegment Theorem, we know that KM=1/2(DC+EF). KM=1/2(66 cm+44 cm). KM=1/2(110 cm). KM=55 cm.

Hope this helps and makes sense!

4 0

2 years ago

The medians of TUV are TX, UY, and VW. They meet at a single point Z.

Anettt [7]

Answer:

TZ = 10 units

UY = 12 units

ZW = 11 units

Step-by-step explanation:

Point Z is the centroid of ΔTUV.

Since, centroid of a triangle is located on each median so that it divides each median in the ratio of 2 : 1

Therefore, TZ = 2(ZX)

TZ = 2(5) = 10 units

UY = UZ + ZY

= UZ + $\frac{1}{2}(UZ)$

= $\frac{3}{2}UZ$

= $\frac{3}{2}\times 8$

= 12 units

ZW = $\frac{1}{3}(VW)$

= $\frac{1}{3}(33)$

= 11 units

3 0

2 years ago