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3 years ago

PLEASE HELP WILL MARK BRAINLIEST ANSWER THANKYOU SO MUCH I RELLY APRICTE IT

Mathematics

1 answer:

babymother [125]3 years ago

8 0

400 mm would be the answer

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2. Which of these describes a unique polygon?

dimulka [17.4K]

Answer: A

Step-by-step explanation:

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4 years ago

Find the area of figure 1. a -12 units2 b- 14 units2 c- 8 units2 d- 10 units2

Brilliant_brown [7]

Answer:

Step-by-step explanation:

if you look at the chart. it goes up five and has a width of 2. multiply 5 x 2 = you get 10

3 0

3 years ago

Read 2 more answers

Select the correct answer.

natulia [17]

Answer:

Step-by-step explanation:

just think about it :

can it move up or down ? no, because for a specific input value still the same functional result is calculated (nothing is getting bigger or smaller).

all that is happening that way is that now, with using g(x), the original f(x) functional values happen now 2 units "later" = to the right (if you consider the x-axis a time line growing to the right). we are getting the functional value of f(x-2) at x and not at x-2 for g(x).

for example

the functional values are for x² (just some integers to make it easier) :

x = 1, 2, 3, 4, 5, ...

getting

f(1), f(2), f(3), f(4), f(5), ...

leading to

1², 2², 3² 4², 5², ...

which is

1, 4, 9, 16, 25, ...

now, let's say we start looking at x = 3

x = 3, 4, 5, 6, 7, ...

getting

g(3), g(4), g(5), g(6), g(7), ..

leading to

1², 2², 3² 4², 5², ...

which is

1, 4, 9, 16, 25, ...

so, now we are getting the functional value at e.g. x = 5 that we got originally for x = 3 (9).

therefore, under g(x) the original functional values still "happen", they just simply "happen" 2 units "later" (to the right).

in the same way

g(x) = f(x+2) moves everything 2 units to the left (now things are happening "earlier").

8 0

2 years ago

This exercise illustrates that poor quality can affect schedules and costs. A manufacturing process has 120 customer orders to f

Aliun [14]

Answer:

a. P(X = 0) = 0.02586

b. $\mathbf{P(X \leq 2 ) =0.2879}$

c. $\mathbf{P(X \leq 5 ) =0.8387}$

Step-by-step explanation:

From the given information:

a. If the manufacturer stocks 120 components, what is the probability that the 120 orders can be filled without reordering components?

$P(X = 0)=(^{120}_{0}) (0.03)^0 (1-0.03)^{n-0}$

$P(X = 0)=\dfrac{120!}{0!(120-0)!} (0.03)^0 (1-0.03)^{n-0}$

P(X = 0) = 1 × 1 ( 0.97)¹²⁰ ⁻ ⁰

P(X = 0) = 0.02586

b. ) If the manufacturer stocks 122 components, what is the probability that the 120 orders can be filled without reordering components?

$P(X \leq 2 ) = [ P(X=0) + P(X =1) + P(X = 2) ]$

$P(X \leq 2 ) = [(^{122}_{0})(0.03)^0 (0.97)^{122-0}+(^{122}_{1})(0.03)^1 (0.97)^{122-1}+(^{122}_{2})(0.03)^2 (0.97)^{122-2}]$ $P(X \leq 2 ) = [\dfrac{122!}{0!(122-0)! } \times 1 \times (0.97)^{122}+\dfrac{122!}{1!(122-1)! } \times (0.03) (0.97)^{121}+\dfrac{122!}{2!(122-2)! } \times 9 \times 10^{-4} \times (0.97)^{120}]$

$P(X \leq 2 ) = [(1 \times 1 \times 0.02433 )+(122 \times (0.03) \times 0.025083)+(7381 \times 9 \times 10^{-4} \times 0.02586)]$

$\mathbf{P(X \leq 2 ) =0.2879}$

(c) If the manufacturer stocks 125 components, what is the probability that the 120 orders can be filled without reordering components?

$P(X \leq 5 ) = [ P(X=0) + P(X =1) + P(X = 2) +P(X = 3)+P(X = 4)+ P(X = 5) ]$

$P(X \leq 5 ) = [(^{122}_{0})(0.03)^0 (0.97)^{122-0}+(^{122}_{1})(0.03)^1 (0.97)^{122-1}+(^{122}_{2})(0.03)^2 (0.97)^{122-2} + (^{122}_{3})(0.03)^3 (0.97)^{122-3} + (^{122}_{4})(0.03)^4 (0.97)^{122-4}+ (^{122}_{5})(0.03)^5 (0.97)^{122-5}]$ $P(X \leq 5 ) = [\dfrac{122!}{0!(122-0)! } \times 1 \times (0.97)^{122}+\dfrac{122!}{1!(122-1)! } \times (0.03) (0.97)^{121}+\dfrac{122!}{2!(122-2)! } \times 9 \times 10^{-4} \times (0.97)^{120} + \dfrac{122!}{3!(122-3)! }*(0.03)^3(0.97)^{122-3)}+ \dfrac{122!}{4!(122-4)! }*(0.03)^4(0.97)^{122-4)} +\dfrac{122!}{5!(122-5)! } *(0.03)^5(0.97)^{122-5)}]$

$\mathbf{P(X \leq 5 ) =0.8387}$

5 0

3 years ago

If two sides of a triangle measure 5 and 12 the length of the third side could be

Artemon [7]

A) 5

Two sides of a triangle have to be the same size. IF we aren't talking about a scalene.

3 0

3 years ago