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bulgar [2K]
4 years ago
7

Use the drop-down menu to complete the statement about Earth’s magnetism. Earth’s magnetic field is generated in the core, which

is made of that is constantly .
Physics
2 answers:
MArishka [77]4 years ago
8 0

Answer:

1.-core

2.iron

3.churning

Explanation:

just got it right on edg

Maurinko [17]4 years ago
5 0
Earth’s magnetic field is generated in the core, which is made of ( IRON) that is constantly (MOVING)i got it right <span> . </span>
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Use Percentages Given that the molecular mass of magnesium
ira [324]

Answer:

27%

Explanation:

15.999 divided by 58.32 = .27433128

Move the decimal place over 2 places.

27%

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4 years ago
A car accelerates from 20.0 m/s to 28.0 m/s over a distance of 50.0 m. What is the car’s acceleration?
Blababa [14]

Answer:

Explanation:

V^2=V^2_o+2a(x_f-x_i)

28^2=20^2+2a(50)\\784=400+100a\\384=100a\\a=3.84m/s^2

5 0
3 years ago
How does a tire of a car interact with the road​
choli [55]

Answer:

friction

Explanation:

the road is the pathway for the vehicle so the tures create friction to stay sturdie

7 0
3 years ago
Which of the following types of waves carries the most energy?
Umnica [9.8K]
C.) ultraviolet 
Ultraviolet because it is the most harmful of them all. Just like the x-rays, amirite?
7 0
3 years ago
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Derive an equation for the acceleration of block 3 for any arbitrary values of m3 and m2. Express your answer in terms of m3, m2
dybincka [34]

Complete question is;

Block 1 is resting on the floor with block 2 at rest on top of it. Block 3, at rest on a smooth table with negligible friction, is attached to block 2 by a string that passes over a pulley, as shown in the attachment below. The string and pulley have negligible mass.

Block 1 is removed without disturbing block 2.

Derive an equation for the acceleration of block 3 for any arbitrary values of m3 and m2. Express your answer in terms of m3, m2, and physical constants as appropriate.

Answer:

a = (m2)g/(m3 + m2)

Explanation:

Looking at the attached image, if we consider the free body diagram for block 3, by using Newton's first law of motion, we will arrive at the formula;

T = (m3)a - - - (eq 1)

where;

T is the tension in the string

a is acceleration

m3 is mass of block 3

Meanwhile doing the same with Block 2, the free body diagram would give us the formula; (m2)g - T = (m2)a

Making T the subject gives us;

T = (m2)g - (m2)a - - - (eq 2)

where;

g is acceleration due to gravity

T is the tension in the string

a is acceleration

m2 is mass of block 2

To solve for the acceleration, we will just substitute (m3)a for T in eq 2.

Thus;

(m3)a = (m2)g - (m2)a

(m3)a + (m2)a = (m2)g

a(m3 + m2) = (m2)g

a = (m2)g/(m3 + m2)

3 0
3 years ago
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