Take into account that density and relative density are given by:
Take into account that the volume associated to each of the given sustances in the table is determined by the Level Difference (because it is the change in the volume of the water of the recipient in which the substance is immersed).
The density of water in kg/m^3 is 1000 kg/m^3.
Due to the density must be given in kg/m^3, it is necessary to express the volumes of the table in m^3 and mass in kg, then, consider the following conversion factor:
1 m^3 = 1000000 ml
1 kg = 1000 g
Then, you obtain the following results:
Brass:
Cooper:
Answer:
2682
Explanation:
Work done is given by :
Work = Force x distance
= mg x d
So, work done in lifting the box of 23 kg up to my waist of 1 m high is :
W = mg x d
= 23 x 9.18 x 1
= 211.14
Now work done carrying the box horizontally 6 meters across the room is
W = mg x d
= 23 x 9.18 x 6
= 1266.84
Work done in placing the box on the shelf that is 5.7 m above the ground is
W = mg x d
= 23 x 9.18 x 5.7
= 1203.49
So the total work done is = 211.14 + 1266.84 + 1203.49
= 2681.47
= 2682 (rounding off)
Answer:
d
Explanation:
Correct answer: D). All of the above The particulate control device is a device that is used for the separation of the material that is of a bigger size as compared to filter. In the factory smokestack, the particulate control device filters the particulate matter that is known to cause air pollution. In the vacuum cleaner, a fine dust particle is filtered out. In the laundry dryer, the water and dirt molecule is allowed to pass through it. Hence, all the options are correct.so therefore your answer would be all
Speed with which initially car is moving is 21 m/s
Reaction time = 0.50 s
distance traveled in the reaction time d = v t
d = 21 * 0.50 = 10.5 m
deceleration after this time = -10 m/s^2
now the distance traveled by the car after applying bakes
so total distance moved before it stop
d = 22.05 + 10.5 = 32.55 m
so the distance from deer is 35 - 32.55 = 2.45 m
now to find the maximum speed with we can move we will assume that we will just touch the deer when we stop
so our distance after brakes are applied is d = 35 - 10.5 = 24.5 m
again by kinematics
so maximum speed would be 22.1 m/s
Answer:
Explanation:
First of all we shall find the velocity at equilibrium point of mass 1.2 kg .
It will be ω A , where ω is angular frequency and A is amplitude .
ω = √ ( k / m )
= √ (170 / 1.2 )
= 11.90 rad /s
amplitude A = .045 m
velocity at middle point ( maximum velocity ) = 11.9 x .045 m /s
= .5355 m /s
At middle point , no force acts so we can apply law of conservation of momentum
m₁ v₁ = ( m₁ + m₂ ) v
1.2 x .5355 = ( 1.2 + .48 ) x v
v = .3825 m /s
= 38.25 cm /s
Let new amplitude be A₁ .
1/2 m v² = 1/2 k A₁²
( 1.2 + .48 ) x v² = 170 x A₁²
( 1.2 + .48 ) x .3825² = 170 x A₁²
A₁ = .0379 m
New amplitude is .0379 m
