Answer:
The net force acting on the person is, F = 560 N
Explanation:
Given data,
The downward acceleration of the elevator, a = 1.8 m/s²
The weight of the person is, W = mg
= 686 N
Therefore the mass of the person,
m = W /g
= 686 / 9.8
= 70 kg
The net force acting on the person,
F = mg - ma
= 686 - 70 x 1.8
= 560 N
Hence, the net force acting on the person is, F = 560 N
Answer:
1317.4 m
Explanation:
We are given that
Angle=
Initial speed =
We have to find the horizontal distance covered by the shell after 5.03 s.
Horizontal component of initial speed=
Vertical component of initial speed=
Time=t=5.03 s
Horizontal distance =
Using the formula
Horizontal distance=
Horizontal distance=1317.4 m
Hence, the horizontal distance covered by the shell=1317.4 m
Answer: 50π m ≈ 157 m
Explanation:
100 rev/min (2π rad/rev) / (60 sec/min) = 3⅓π rad/s
d = ωrt = 3⅓π(0.50)(30) = 50π m ≈ 157 m