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goldfiish [28.3K]
3 years ago
14

A cheetah can run up to 70 mph. how long will it take to catch a antelope running 45 mph, if the antelope has a 50 yard head sta

rt?
Physics
1 answer:
Nana76 [90]3 years ago
5 0
As 1mile = 1760 yards
* represents multiplication. 

Cheetah speed = 70mph = (70 * 1760) / 3600 = 34.22 yards per seconds
Distance covered by cheetah = 34.22 * t ------------------- (1)

Now
Antelope speed = 45mph = (45 * 1760) / 3600 =  22 yards per seconds
Distance covered by antelope = 22 * t + 50--------------------- (2)
equating both equation (1) and (2);
34.22 * t = 22 * t + 50
12.22 * t = 50
t = 4.091 seconds
Hence the cheetah will catch the antelope after 4.091 seconds

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5 0
3 years ago
- A person is on an elevator that moves
Mademuasel [1]

Answer:

The net force acting on the person is, F = 560 N

Explanation:

Given data,

The downward acceleration of the elevator, a = 1.8 m/s²

The weight of the person is, W = mg

                                                          = 686 N

Therefore the mass of the person,

                                           m = W /g

                                               = 686 / 9.8

                                               = 70 kg

The net force acting on the person,

                                           F = mg - ma

                                               = 686 - 70 x 1.8

                                               = 560 N

Hence, the net force acting on the person is, F = 560 N

5 0
3 years ago
An artillery shell is launched on a flat, horizontal field at an angle of α = 40.8° with respect to the horizontal and with an i
Lina20 [59]

Answer:

1317.4 m

Explanation:

We are given that

Angle=\alpha=40.8^{\circ}

Initial speed =v_0=346m/s

We have to find the horizontal distance covered  by the shell after 5.03 s.

Horizontal component of initial speed=v_{ox}=v_0cos\theta=346cos40.8=261.9m/s

Vertical component of initial speed=v_{oy}=346sin40.8=226.1m/s

Time=t=5.03 s

Horizontal distance =Horizontal\;velocity\times time

Using the  formula

Horizontal distance=261.9\times 5.03

Horizontal distance=1317.4 m

Hence, the horizontal distance covered by the shell=1317.4 m

8 0
3 years ago
A 12 kg block is moving right with a constant acceleration of 4 m/s2. What is the magnitude of the force on the block?
max2010maxim [7]
Force=ma
=12kgx4m/s2
= 48 N
3 0
3 years ago
a disk of a radius 50 cm rotates at a constant rate of 100 rpm. what distance in meters will a point on the outside rim travel d
vlabodo [156]

Answer: 50π m ≈ 157 m

Explanation:

100 rev/min (2π rad/rev) / (60 sec/min) = 3⅓π rad/s

d = ωrt = 3⅓π(0.50)(30) = 50π m ≈ 157 m

8 0
3 years ago
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