Answer:
NO
Step-by-step explanation:
The changeability of a sampling distribution is measured by its variance or its standard deviation. The changeability of a sampling distribution depends on three factors:
- N: The number of observations in the population.
- n: The number of observations in the sample.
- The way that the random sample is chosen.
We know the following about the sampling distribution of the mean. The mean of the sampling distribution (μ_x) is equal to the mean of the population (μ). And the standard error of the sampling distribution (σ_x) is determined by the standard deviation of the population (σ), the population size (N), and the sample size (n). That is
μ_x=p
σ_x== [ σ / sqrt(n) ] * sqrt[ (N - n ) / (N - 1) ]
In the standard error formula, the factor sqrt[ (N - n ) / (N - 1) ] is called the finite population correction. When the population size is very large relative to the sample size, the finite population correction is approximately equal to one; and the standard error formula can be approximated by:
σ_x = σ / sqrt(n).
A.
y = 7 - |x| = 7 - 2 = 5
b.
y = x² - 1 = 2² - 1 = 4 - 1 = 3
c.
y = √(x + 14) = √(2 + 14) = √16 = 4
Step 1: Find the value of one variable in terms of the other.
Step 2: Substitute the value you just found for this variable in the other equation.
Step 3: Use your new value for the second variable to find the first.
Now that we know the values for a and b we can find the value of 4a+b.
Answer:
i dont khow
i guess true
Step-by-step explanation:
