3 years ago

I can't solve this equation pleas help!x^2+2x+8=0

1 answer:

8 0

$x^2+2x+8=0\\
x^2+2x+1+7=0\\
(x+1)^2=-7\\
x+1=-\sqrt{-7} \vee x+1=\sqrt{-7}\\
x=-1-\sqrt7 i \vee x=-1+\sqrt7 i$

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(a) The confidence interval is: 0.0304 ≤ π ≤ 0.0830.

(b) Upper confidence bound = 0.0787

Step-by-step explanation:

(a) The confidence interval for p (proportion) can be calculated as

$p \pm z*\sigma_{p}$

$\sigma=\sqrt{\frac{\pi*(1-\pi)}{N} }\approx\sqrt{\frac{p(1-p)}{N} }$

NOTE: π is the proportion ot the population, but it is unknown. It can be estimated as p.

$p=17/300=0.0567\\\\\sigma=\sqrt{\frac{p(1-p)}{N} }=\sqrt{\frac{0.0567(1-0.0567)}{300} }=0.0134$

For a 95% two-sided confidence interval, z=±1.96, so

$\\LL = p-z*\sigma=0.0567 - (1.96)(0.0134) = 0.0304\\UL =p+z*\sigma= 0.0567 + (1.96)(0.0134) = 0.0830\\\\$

The confidence interval is: 0.0304 ≤ π ≤ 0.0830.

(b) The confidence interval now has only an upper limit, so z is now 1.64.

$UL =p+z*\sigma= 0.0567 + (1.64)(0.0134) = 0.0787$

The confidence interval is: -∞ ≤ π ≤ 0.0787.

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