Question

I can't solve this equation pleas help!x^2+2x+8=0

Answer 1

$x^2+2x+8=0\\ x^2+2x+1+7=0\\ (x+1)^2=-7\\ x+1=-\sqrt{-7} \vee x+1=\sqrt{-7}\\ x=-1-\sqrt7 i \vee x=-1+\sqrt7 i$