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Dovator [93]
3 years ago
11

A student solves the equation StartFraction x + 3 Over 2 EndFraction = StartFraction 3 x + 5 Over 5 EndFraction using the steps

in the table.
Original equation
StartFraction x + 3 Over 2 EndFraction = StartFraction 3 x + 5 Over 5 EndFraction
Cross multiplication
5 (x + 3) = 2 (3x + 5)
Distributive property
5 x + 15 = 2 (3 x + 5)
Subtraction property of equality
5 = x

Which method of solving for the variable could be used instead of cross multiplication?
distributing x + 3 and then 3x + 5 to both sides of the equation
distributing x – 3 and then 3x – 5 to both sides of the equation
using the multiplication property of equality to multiply both sides of the equation by 10
using the multiplication property of equality to multiply both sides of the equation by One-tenth
Mathematics
1 answer:
bonufazy [111]3 years ago
7 0

using the multiplication property of equality to multiply both sides of the equation by 10

Step-by-step explanation:

Given equation is:

\frac{x+3}{2} = \frac{3x+5}{5}

One method to solve this equation is cross-multiplication which the student has used.

One of the alternate method can be multiplying both sides by the LCM of numerators of fractions on both sides

So multiplying both sides by 10 (multiplication property of equality)

\frac{x+3}{2} * 10 = \frac{3x+5}{5} * 10\\5(x+3) = 2(3x+5)\\5x+15 = 6x+10\\5x+15-10 = 6x\\6x = 5x+5\\6x-5x = 5\\x = 5

The alternate method of LCM produces the same answer so the correct answer is:

using the multiplication property of equality to multiply both sides of the equation by 10

Keywords: Linear equations, variables

Learn more about linear equations at:

  • brainly.com/question/11229113
  • brainly.com/question/11234838

#LearnwithBrainly

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In the general population, the mean IQ is 100 with a standard deviation of 15. Dr. Robbins wants to see if a class of statistics
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From the information given, a right-tailed test using the z-distribution is appropriate.

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At the alternative hypothesis, it is <u>tested if they are significantly smarter</u>, that is, their mean IQ is greater than 100, hence:

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How do you solve this equation 7(3)+(-9)×(-4)=
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Hello!

To solve this equation, we will need to use PEMDAS (parentheses, then exponents, then multiplication/division, then addition/subtraction).

7(3) + (-9) x (-4) =

21 + (-9) x (-4) =

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I hope this helps you! Have a lovely day!

- Mal

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