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antoniya [11.8K]
3 years ago
15

A miner has 3 kilograms of gold dust. She needs to share it evenly with four partners. How much gold should each of the five peo

ple get?
250 g
300 g
500 g
600 g
Mathematics
2 answers:
vredina [299]3 years ago
4 0
D. 600 g 3000 g / 5 ppl = 600 g per person
ICE Princess25 [194]3 years ago
3 0

Answer:

Option d. 600 g.

Step-by-step explanation:

A miner has 3 kilograms of gold dust.

she needs to share it evenly with four partners.

As we know 1 kilograms = 1000 grams

Therefore,    3 kilograms = 1000 × 3 = 3000 grams

Now we divide it with 5 partners.

3000 ÷ 5 = 600 grams

Each of the five people will get 600 grams gold.

Option d. 600 g.

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The first term in a geometric sequence is 54, and the 5th term is 2 / 3. Find an explicit form for the geometric sequence.
quester [9]

Answer:  ar^{n-1}=54(\dfrac{1}{3})^{n-1}

Step-by-step explanation:

The nth term for a geometric sequence is given by :-

a_n=ar^{n-1}    (1)

We are given that The first term in a geometric sequence is 54. i.e. a=54

5th term=\dfrac{2}{3}   (2)

Put n=5 and a= 54 in (1), we get

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From (2) and (3), we have

\Rightarrow(54)r^{4}=\dfrac{2}{3}\\\\\Rightarrow r^4=\dfrac{2}{3}\times\dfrac{1}{54}=\dfrac{1}{3\times27}=\dfrac{1}{81}\\\\\Rightarrow\ r=(\dfrac{1}{81})^{\frac{1}{4}}=\dfrac{1}{3}

Explicit form for the geometric sequence: ar^{n-1}=54(\dfrac{1}{3})^{n-1}

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natta225 [31]

y = 1/3x

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See attached picture:




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Answer:

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Step-by-step explanation:

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