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Luda [366]
2 years ago
11

Use the quadratic formula to solve 2^2 − 5 − 5 = 0 The formula is : ( -b ± √b^2 - 4ac ) / 2a

Mathematics
1 answer:
Serggg [28]2 years ago
8 0

Answer:

x = 5/4 + √65/4 or x = 5/4 - √65/4

Step-by-step explanation:

I'm assuming you mean 2x^2-5x-5=0?

x = ( -b ± √b^2 - 4ac ) / 2a

x = ( -(-5) ± √(-5)^2 - 4(2)(-5) ) / 2(2)

x = ( 5 ± √(25 + 40) ) / 4

x = ( 5 ± √65 ) / 4

x = 5/4 ± √65/4

Therefore, x = 5/4 + √65/4 or x = 5/4 - √65/4

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How do I Graph y=  –73x+2 .
Romashka-Z-Leto [24]

Answer:

See attachment

Step-by-step explanation:

You can obtain any two points on the graph of y=-73x+2 and use it to draw its graph.

When x=0, y=-73*0+2=2

So you plot (0,2)

When x=1, y=-73*1+2=-71

You again plot (1,-71).

With a straight edge you can now draw a straight line through the two points.

See attachment

4 0
3 years ago
2x=10y+14, 6x-2y=2x+28 how do I solve this problem using algebraic method?
yuradex [85]
PEMDAS- Parenthesis, Exponent, Multiplication, Division, Addition, Subtraction.

4 0
3 years ago
What is the inverse of the function g(x)=7x+3/x-5?
Ad libitum [116K]

Answer:

g(x) = (5x + 3)/ x - 7

Step-by-step explanation:

Let g(x) = y

y = (7x + 3)/x - 5

Make x the subject

xy - 5y = 7x + 3

xy - 7x = 5y + 3

x(y - 7) = 5y + 3

x = (5y + 3)/ y - 7

Therefore, the inverse of the function = (5x + 3)/ x - 7

8 0
2 years ago
Does the following mapping diagram represent a function?
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a

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3 0
2 years ago
An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from so
alexgriva [62]

Solution :

Let p_1 and p_2  represents the proportions of the seeds which germinate among the seeds planted in the soil containing 3\% and 5\% mushroom compost by weight respectively.

To test the null hypothesis H_0: p_1=p_2 against the alternate hypothesis  H_1:p_1 \neq p_2 .

Let \hat p_1, \hat p_2 denotes the respective sample proportions and the n_1, n_2 represents the sample size respectively.

$\hat p_1 = \frac{74}{155} = 0.477419

n_1=155

$p_2=\frac{86}{155}=0.554839

n_2=155

The test statistic can be written as :

$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}

which under H_0  follows the standard normal distribution.

We reject H_0 at 0.05 level of significance, if the P-value or if |z_{obs}|>Z_{0.025}

Now, the value of the test statistics = -1.368928

The critical value = \pm 1.959964

P-value = $P(|z|> z_{obs})= 2 \times P(z< -1.367928)$

                                     $=2 \times 0.085667$

                                     = 0.171335

Since the p-value > 0.05 and $|z_{obs}| \ngtr z_{critical} = 1.959964$, so we fail to reject H_0 at 0.05 level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the \text{proportion} of the seeds that \text{germinate differs} with the percent of the \text{mushroom compost} in the soil.

8 0
3 years ago
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