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4 years ago

Convert -1 1/4 into a decimal

Mathematics

2 answers:

makkiz [27]4 years ago

6 0

-1 1/4 as a decimal would be -1.25.

Since -1 is a whole number we would just write that as -1. 1/4 as a decimal is .25.

Nata [24]4 years ago

4 0

-11/4 = -11➗4

So answer would be -2.75

Since 4 goes into -11 two times and the remainder is 3

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A store is selling 5 cans of tomato sauce for $4.50. What is the unit price?

NARA [144]

Hi there! The answer is $0.90

To find the price per unit we must divide the total amount of money by the amount of units sold. So we get the following:
$4.50 / 5 = $0.90

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3 years ago

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4 years ago

4x+6=4+(2x+1) is the answer 6=6

seropon [69]

Answer:

Step-by-step explanation:

4x+6=4+(2x+1)

Opening bracket

4x + 6 = 4 + 2x + 1

Collecting like terms

4x - 2x = 4 + 1 - 6

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3 years ago

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Solve the compound inequality.

agasfer [191]

Answer:

Step-by-step explanation:

Solve each inequality one at a time:

5x ≤ 21 + 2x and

3x ≤ 21 so

x ≤ 7

The other inequality is

3x + 3 ≥ 24 and

3x ≥ 21 so

x ≥ 7

If x is less than or equal to 7 AND greater than or equal to 7, then the solution is all real numbers.

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3 years ago

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

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3 years ago