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sattari [20]
3 years ago
7

Which of Newton's laws accounts for the following statement? "A force cannot act alone." first law second law third law

Physics
2 answers:
enot [183]3 years ago
6 0

Newton's laws A force cannot act  alone is the THIRD LAW!

ki77a [65]3 years ago
4 0

Answer:

"A force cannot act alone" is a statement that belongs to Newton's Third Law, because the forces act in pairs (action and reaction).

Explanation:

Newton's First Law, also called the Law of inertia, indicates that "The whole body perseveres in its state of rest or uniform rectilinear motion, unless the sea is forced to change its state by forces printed on it." This means that for a body to leave its state of rest or the motion, it is necessary for a force to act on it.

Newton's Second Law, also called the Fundamental Law of Dynamics, indicates that: "The change of motion is directly proportional to the printed driving force and occurs along a straight line along which that force is printed." This means that the acceleration of a moving object depends on the amount of force that is applied at a given time, in order to modify its trajectory or speed.

Newton's Third Law is also known as the Principle of action and reaction. This law indicates that “Every action has an equal reaction but in the opposite direction” This means that when a body exerts a force (action) on another, it responds with a force of equal magnitude although opposite direction (reaction). Then this law explains the forces that always occur in the form of peers: an action and a reaction.

Finally <u><em>"A force cannot act alone" is a statement that belongs to Newton's Third Law, because the forces act in pairs (action and reaction).</em></u>

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The sides

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3 years ago
An elastic circular bar is fixed at one end and attached to a rubber grommet at the other end. The grommet functions as a torsio
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Answer:

2.1 rad(anticlockwise).

Explanation:

So, we are given the following data or parameters or information in the question above:

=> "The torsional stiffness of the spring support is k = 50 N m/rad. "

=> "If a concentrated torque of mag- nitude Ta = 500 Nm is applied in the center of the bar"

=> "L = 300 mm Assume a shear modu- lus G = 10 kN/mm2 and polar monnent of inertia J = 2000 mln"

Hence;

G × J = 10 kN/mm2 × 2000 mln = 20 Nm^2.

Also, L/2 = 300 mm /2 = 0.15 m (converted to metre).

==> 0.15/20 (V - w) + θ = 0.

==> 0.15/20 (V - w ) = -θ.

Where V = k = 50 N m/rad

w = 183.3 θ.

Therefore, w + Vθ = 500 Nm.

==> 183.3 + 50 θ = 500 Nm.

= 6.3

Anticlockwise,

θ = 2.1 rad.

4 0
3 years ago
What is the car’s average velocity (in m/s) in interval between t=1.0s to t=1.5s?
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Answer:

This question is incomplete

Explanation:

This question is incomplete. However, the formula for velocity is;

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The distance the car covered in the completed question is divided by the difference in the time interval

The difference in the time interval will be = 1.5s - 1.0s = 0.5s

NOTE: the distance must be in meters or be converted to meters

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g (15 points) Picture taken from problem 13-35. A 2000 kg truck is traveling at 25 meters/second. The driver suddenly hits the b
otez555 [7]

Answer:

Δx = 3.99 m

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will make it short and easy.  

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1/2mv2=Δxmgμ            (Note: The masses cancel )

 1/2v2=Δxgμ                  Solve for Δx

where g=9.8  

Δx=v2/(2gμ)                   Δx = 25 / (2 * 9.8 * 0.32)     Δx = 3.99 m

Please let me know if its correct, if not report it so we can correct it.

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