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mrs_skeptik [129]
2 years ago
5

if length of the spring is doubled, what will happen to its time period? if mass of the spring is doubled and spring constant wi

ll be halved, what will happen to the periods of the spring? chegg
Physics
1 answer:
melamori03 [73]2 years ago
5 0

If the length of the spring is doubled, there will be no effect on its period.

If the mass of the spring is doubled and the spring constant is halved, then its period will be doubled.

The Simple Harmonic Motion is a type of periodic motion and one of its examples is the spring-mass system.

The period of a spring mass system is given by the following equation,

T= 2π√m/√k

Here, T= period of spring

m= Mass of the body attached to the spring

k= Spring constant

According to the above equation, the period of a spring depends on the mass of the body and the spring constant.

It is independent of the length of the spring.

Therefore, if the length of spring is doubled then there will be no effect on its period.

If the mass of spring is doubled and the spring constant is halved, then the equation becomes

T'= 2π√2m/√k/2

T'= √4 x 2π√m/√k

T'= 2 x T

Hence, if the mass of the spring is doubled and the spring constant is halved, its period will be doubled.

To know more about the "spring-mass system", refer to the following link:

brainly.com/question/13156044?referrer=searchResults

#SPJ4

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5. Suppose a skydiver (mass = 75kg) is falling toward the Earth. When the skydiver is 100m above the Earth he is moving at 60m/s
Anna71 [15]

1) Gravitational potential energy: 73 500 J

2) Kinetic energy: 135 000 J

3) Mechanical energy: 208 500 J

Explanation:

1)

The gravitational potential energy of an object is the energy possessed by the object due to its position in the Earth's gravitational field, and it is given by

U=mgh

where

m is the mass of the object

g=9.8 m/s^2 is the acceleration of gravity

h is the height of the object relative to the ground

For the skydiver in this problem,

m = 75 kg is his mass

h = 100 m is his height above the Earth

Substituting, we find

U=(75)(9.8)(100)=73500 J

2)

The kinetic energy of a body is the energy due to its motion, and it is given by

K=\frac{1}{2}mv^2

where

m is the mass of the body

v is its speed

For the skydiver in this problem,

m = 75 kg is his mass

v = 60 m/s is his speed

Substituting, we find the kinetic energy

K=\frac{1}{2}(75)(60)^2=135000 J

3)

The mechanical energy of an object is the sum of the gravitational potential energy and the kinetic energy of the object:

E=U+K

where

U is the gravitational potential energy

K is the kinetic energy

For the skydiver in this problem,

U = 73,500 J is the gravitational potential energy

K = 135,000 J is the kinetic energy

Substituting, we find

E=73,500 + 135,000 = 208,500 J

Learn more about potential energy and kinetic energy:

brainly.com/question/1198647

brainly.com/question/10770261

brainly.com/question/6536722

#LearnwithBrainly

3 0
4 years ago
Need help in this question ???? Hurry please
Digiron [165]

Answer:

how quickly or slowly the object is moving

Hope this helps

7 0
3 years ago
If the mercury barometer is 75.58 cm at the base of the mountain and 66.37 cm at the summit. What is the height of the mountain?
Licemer1 [7]

Answer:

5016.2446

Explanation:

3 0
3 years ago
If you fired a rifle straight upwards at 1000 m/s, how far up will the bullet get?
nadya68 [22]

Answer:

h = 51020.40 meters

Explanation:

Speed of the rifle, v = 1000 m/s

Let h is the height gained by the bullet. It can be calculated using the conservation of energy as :

\dfrac{1}{2}mv^2=mgh

h=\dfrac{v^2}{2g}

h=\dfrac{(1000\ m/s)^2}{2\times 9.8\ m/s^2}                    

h = 51020.40 meters

So, the bullet will get up to a height of 51020.40 meters. Hence, this is the required solution.          

4 0
3 years ago
The displacement ‘x’of a particle is dependent on time ‘t’according to the relation X= 3 -5t +<img src="https://tex.z-dn.net/?f=
rusak2 [61]

Answer:

Explanation:

A.

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