I put my answer as 31 C but it was wrong?
1 answer:
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<u>Answer:</u> The pH of acid solution is 4.58
<u>Explanation:</u>
To calculate the number of moles for given molarity, we use the equation:
.....(1)
- <u>For KOH:</u>
Molarity of KOH solution = 1.1000 M
Volume of solution = 41.04 mL
Putting values in equation 1, we get:
- <u>For propanoic acid:</u>
Molarity of propanoic acid solution = 0.6100 M
Volume of solution = 224.9 mL
Putting values in equation 1, we get:
The chemical reaction for propanoic acid and KOH follows the equation:
<u>Initial:</u> 0.1372 0.04514
<u>Final:</u> 0.09206 - 0.04514
Total volume of solution = [224.9 + 41.04] mL = 265.94 mL = 0.26594 L (Conversion factor: 1 L = 1000 mL)
To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:
We are given:
= negative logarithm of acid dissociation constant of propanoic acid = 4.89
pH = ?
Putting values in above equation, we get:
Hence, the pH of acid solution is 4.58