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gregori [183]
3 years ago
9

I'm trying to do question number 2.56

Chemistry
1 answer:
Lunna [17]3 years ago
8 0
The answer is in the picture which is given below:

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Erioglucine is a blue-colored dye that absorbs its complementary color, red, in aqueous solution around 645 nm. Unfortunately, t
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Answer:

For the control experiment: 0.0552 M of aqueous solution of erioglaucine has absorbance of 0.035 M\\

From Lambert-Beer's law we know:

Absorbance = e\cdot c \cdot l\\

Here; e is the molar absorptivity coefficient of erioglaucine

l = length of cuvette in which the solution is taken = 1 cm

A sorbance by the erioglaucine = total absorbance - absorbance by distilled water = 0.331-0.019 = 0.312

So; by putting the values in the above equation; we get:

0.312 = 0.0552 M \cdot e\cdot~1cm\\

So; e = \frac{0.331}{0.0552} M^{-1}cm^{-1}= 5.65 M^{-1}cm^{-1}

The molar absorptivity coefficient of erioglaucine is 5.65 M^{-1}cm^{-1}\\

The absorbance of erioglaucine in distilled water (contaminated with metal ions) is: 0 .217

The absorbance of distilled water is 0.019

So; absorbance of erioglaucine itself is : 0.217-0.019 = 0.198

Again using Lambert Beer law; we get:

A= e\cdot c\cdot l

0.198 = 5.65 M^{-1}cm^{-1} \cdot  c \cdot  1 cm ( c = concentrartion)

c = 0.198/5.65 M = 0.035 M

The concentration of the erioglaucine is 0.035 M\\

Explanation:

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Answer:a

Explanation:

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Option D. Activation energy

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