The box has volume
11 in × 3 in × <em>x</em> in = 33<em>x</em> in³
and surface area
2 (11 in × 3 in + 11 in × <em>x</em> in + 3 in × <em>x</em> in) = (66 + 28<em>x</em>) in²
The volume and area have the same value if
33<em>x</em> = 66 + 28<em>x</em>
Solve this equation for <em>x</em> :
33<em>x</em> - 28<em>x</em> = 66
5<em>x</em> = 66
<em>x</em> = 66/5 = 13.2
Answer:
4(s+1)
Step-by-step explanation:
(s+12) + (3s -8)
s+12+(3s-8)
s+12+3s-8
4s+12-8
4s+4
4(s+1)
Answer:
a. Required system of equations is:
c+p = 10
5c+4p = 46
b. 6 cakes were sold
Step-by-step explanation:
Let p be the number of pies and c be the number of cakes.
Then according to given statement " the store sold 10 baked goods"

And
"A cake costs $5 and a pie costs $4"

Using equation 1,

Putting this value of c in equation 2:

Putting p = 4 in equation 1

Hence,
a. Required system of equations is:
c+p = 10
5c+4p = 46
b. 6 cakes were sold