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3 years ago

In the division problem 8 ÷ 2 = 4, which is the dividend?

Mathematics

2 answers:

Alexxandr [17]3 years ago

8 0

The dividend would be 8

Lelu [443]3 years ago

3 0

8 is the dividend. 2 is the divisor. 4 is the quotient.....................

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System of equations 2x+1=5

yawa3891 [41]

x=2 :)

2x+1-1=5-1

2x=4

2/2x=4/2

x=2

if you do the opposite on one side you gotta do it on the other :)))

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3 years ago

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Solve the equation: -2x+3=5 Show your work.

vlabodo [156]

-2x+3=5
Subtract 3 from both sides
-2x=2
Divide both sides by -2 so that the only thing remaining on one side is the variable x
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What is the domain and range to this problem?

prohojiy [21]

Answer:

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Step-by-step explanation:

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3 years ago

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KonstantinChe [14]

Answer:

first one is a 20 prcent decrease from x to y

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Step-by-step explanation:

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3 years ago

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Find the derivative of ln(cosx²).

RoseWind [281]

Answer:

$\displaystyle \frac{dy}{dx} = -2x \tan (x^2)$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle y = \ln (\cos x^2)$

Step 2: Differentiate

Logarithmic Differentiation [Derivative Rule - Chain Rule]: $\displaystyle y' = \frac{(\cos x^2)'}{\cos x^2}$
Trigonometric Differentiation [Derivative Rule - Chain Rule]: $\displaystyle y' = \frac{-\sin x^2 (x^2)'}{\cos x^2}$
Basic Power Rule: $\displaystyle y' = \frac{-2x \sin x^2}{\cos x^2}$
Rewrite [Trigonometric Identities]: $\displaystyle y' = -2x \tan (x^2)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

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3 years ago