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Alex17521 [72]
2 years ago
11

Use the model to find the missing number in the pair of equivalent expressions.

Mathematics
1 answer:
Anastaziya [24]2 years ago
4 0

Answer:

3

Reasoning:

3(5+3)=15+9

Distribute three to the numbers to get 15+9.

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vagabundo [1.1K]
So the original shoes cost 100%, but you are paying 15% less than 100%. 100-15 is 85, so 85% or .85 is your answer.
5 0
3 years ago
Solve for N. -N/5= -5
Afina-wow [57]
(-N)/5=-5
(-N)=(-5)(5)
(-N)=-25
(-1)(N)=(-25)
N=25
5 0
2 years ago
Read 2 more answers
Answer my question for brainiest
11Alexandr11 [23.1K]

Answer:

-13 = n - 4

Step-by-step explanation:

-13 is four less than a number n

so four less than n  can be written as n - 4

-13 = n - 4

n= -9

8 0
3 years ago
How do I find the domain n range of this graph​
motikmotik

Domain = {-3, 2}

Range = All real numbers

We can represent the range in interval notation as (-\infty, \infty) which is basically saying -\infty < y < \infty. The range is all real numbers due to the arrows meaning the graph extends up and down forever. So any y value is possible.

Notice with the domain we only have 2 valid x values -3 and 2. No other x values are allowed. Normally we use an interval of some kind to set up the domain, but we only have a set of values instead. The curly braces indicate "set".

7 0
3 years ago
Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated
Illusion [34]

Answer:

x=-2,0,3

Step-by-step explanation:

We have been given a function f(x)=15x^3-15x^2-90x. We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

15x^3-15x^2-90x=0

Now, we will factor our equation. We can see that all terms of our equation a common factor that is 15x.

Upon factoring out 15x, we will get:

15x(x^2-x-6)=0

Now, we will split the middle term of our equation into parts, whose sum is -1 and whose product is -6. We know such two numbers are -3\text{ and }2.

15x(x^2-3x+2x-6)=0

15x((x^2-3x)+(2x-6))=0

15x(x(x-3)+2(x-3))=0

15x(x-3)(x+2)=0

Now, we will use zero product property to find the zeros of our given function.

15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0

15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0

\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0

x=0\text{ (or) }x=3\text{ (or) }x=-2

Therefore, the zeros of our given function are x=-2,0,3.

7 0
3 years ago
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