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2 years ago

Use the model to find the missing number in the pair of equivalent expressions.

Mathematics

1 answer:

Anastaziya [24]2 years ago

4 0

Answer:

Reasoning:

$3(5+3)=15+9$

Distribute three to the numbers to get 15+9.

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vagabundo [1.1K]

So the original shoes cost 100%, but you are paying 15% less than 100%. 100-15 is 85, so 85% or .85 is your answer.

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3 years ago

Solve for N. -N/5= -5

Afina-wow [57]

(-N)/5=-5
(-N)=(-5)(5)
(-N)=-25
(-1)(N)=(-25)
N=25

5 0

2 years ago

Read 2 more answers

Answer my question for brainiest

11Alexandr11 [23.1K]

Answer:

-13 = n - 4

Step-by-step explanation:

-13 is four less than a number n

so four less than n can be written as n - 4

-13 = n - 4

n= -9

8 0

3 years ago

How do I find the domain n range of this graph

motikmotik

Domain = {-3, 2}

Range = All real numbers

We can represent the range in interval notation as $(-\infty, \infty)$ which is basically saying $-\infty < y < \infty$ . The range is all real numbers due to the arrows meaning the graph extends up and down forever. So any y value is possible.

Notice with the domain we only have 2 valid x values -3 and 2. No other x values are allowed. Normally we use an interval of some kind to set up the domain, but we only have a set of values instead. The curly braces indicate "set".

7 0

3 years ago

Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .