First one is 14
Second one is 45
Third one is 43
Fourth one is 40
Let us always base on the present age. We denote this by x. Now, the age he had 2 years ago would then be denoted as (x-2). Let's equate this to 20 years old.
x - 2 = 20
x = 20 + 2
x = 22 years old
He should be 22 years old now.
Let's check the other condition. After 1 year, his age should be (x+1). Let's equate this to 23 years old.
x + 1 = 23
x = 23 - 1
x = 22
Thus, this is possible if Reuben is 22 years old as of the present.
Acc. to midpoint theorem,
15={(2x+9) + (4x-15)}/2
⇒ 30=2x+9+4x-15
⇒ 30-9+15=6x
⇒ 36/6=x
⇒6=x
WZ= 4x-15
=4*6-15
=24-15=9
Answer:
1/6
Step-by-step explanation:
The centipede that Maria measured was 1 1/12 inches long. If you convert this to an improper fraction it is equal to 13/12 inches. Now to find how much longer Maria's centipede was than Jeromes, you just take 11/12 and minus it from 13/12 which is equal to 2/12 of an inch, which then simplifies to 1/6 of an inch.
Answer:
x = - 9
Step-by-step explanation:
Step 1:
2x - 3 = - 21 Equation
Step 2:
2x = - 18 Add 3 on both sides
Step 3:
- 18 ÷ 2 Divide
Answer:
x = - 9
Hope This Helps :)
