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2 years ago

Are the expressions (-2)^4 and -2^4 equivalent? Explain how you know.

2 answers:

3 0

No, becasue of PEMDAS
so parenthasees first
exponents next
mulitplciation next

(-2)^4=-2 times -2 times -2 times -2=positive number since even number of negative signs

-2^4=-1 times 2^2=-1 times 2 times 2 times 2 times 2=negative number since odd number of negative signs

Zarrin [17]2 years ago

3 0

They are not equivalent.
because (-2)^4 is in the parenthesis so the - before 2 are together and both will go to the 4 power so the answer will be: (-2)^4 = 16
but the other one is not in the parenthesis so the - will not go to the 4 power and the answer will be: -2^4 = -16
so 16 is not equivalent to -16 :)))
i hope this is helpful
have a nice day

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Factor 8X squared + 10x + 2

mojhsa [17]

Answer:

2(4x + 1)(x + 1)

Step-by-step explanation:

Given

8x² + 10x + 2 ← factor out 2 from each term

= 2(4x² + 5x + 1)

To factor the quadratic

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 4 × 1 = 4 and sum = + 5

The factors are + 1 and + 4

Use these factors to split the x - term

4x² + x + 4x + 1 ( factor the first/second and third/fourth terms )

= x(4x + 1) + 1 (4x + 1) ← factor out (4x + 1)

= (4x + 1)(x + 1), thus

4x² + 5x + 1 = (4x + 1)(x + 1) and

8x² + 10x + 2 = 2(4x + 1)(x + 1) ← in factored form

3 0

3 years ago

Use the given graph to determine the limit, if it exists. A coordinate graph is shown with a horizontal line crossing the y axis

Lesechka [4]

Answer:

The limit of the function does not exists.

Step-by-step explanation:

From the graph it is noticed that the value of the function is 6 from all values of x which are less than 2. At x=2, the line y=6 has open circle. It means x=2 is not included.

For x<2

$f(x)=6$

The value of the function is -3 from all values of x which are greater than 2. At x=2, the line y=-3 has open circle. It means x=2 is not included.

For x>2

$f(x)=-3$

The value of y is 1 at x=2, because of he close circles on (2,1).

For x=2

$f(x)=1$

Therefore the graph represents a piecewise function, which is defined as

$f(x)=\begin{cases}6& \text{ if } x2 \end{cases}$

The limit of a function exist at a point a if the left hand limit and right hand limit are equal.

$lim_{x\rightarrow a^-}f(x)=lim_{x\rightarrow a^+}f(x)$

The function is broken at x=2, therefore we have to find the left and right hand limit at x=2.

$lim_{x\rightarrow 2^-}f(x)=6$

$lim_{x\rightarrow 2^+}f(x)=-3$

$6\neq-3$

Since the left hand limit and right hand limit are not equal therefore the limit of the function does not exists.

6 0

2 years ago

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andriy [413]

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3 0

2 years ago

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Answer correctly please

Paul [167]

Answer:

$\$272,49$

Step-by-step explanation:

7. $\displaystyle /text{The answer makes sense because since the depreciation rate is 15%, we know that we need to use the "exponential decay" formula.}$

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5. $\displaystyle 1000[0,85]^8 = 272,490525 ≈ \$272,49$

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2. $\displaystyle /text{How much is the stock worth after a depreciation rate of 15% per year?}$

1. $\displaystyle /text{initial amount: $1000, a depreciation rate of 15%, and a time period of 8 years}$

I am joyous to assist you anytime.

5 0

2 years ago

Please solve with explanation 20 points

VashaNatasha [74]

Answer: i don't know but thanks for the points

Step-by-step explanation:

4 0

2 years ago