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ludmilkaskok [199]
3 years ago
12

Write the slope-intercept form (y=mx+b) of the equation of the line through the given points.​

Mathematics
1 answer:
scoundrel [369]3 years ago
4 0

Answer:   y = \frac{4}{5}x-\frac{3}{5}

m = 4/5 is the slope

b = -3/5 is the y intercept

====================================

First find the slope

m = (y2 - y1)/(x2 - x1)

m = (-3 - 1)/(-3 - 2)

m = -4/(-5)

m = 4/5

Then use point-slope form

y - y_1 = m(x - x_1)\\\\y - 1 = \frac{4}{5}(x - 2)\\\\y - 1 = \frac{4}{5}x + \frac{4}{5}(-2)\\\\y - 1 = \frac{4}{5}x - \frac{8}{5}\\\\y = \frac{4}{5}x - \frac{8}{5} + 1\\\\y = \frac{4}{5}x - \frac{8}{5} + \frac{5}{5}\\\\y = \frac{4}{5}x + \frac{-8+5}{5}\\\\y = \frac{4}{5}x - \frac{3}{5}\\\\

The equation is in the form y = mx+b with m = 4/5 as the slope and b = -3/5 as the y intercept.

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Answer:

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Step-by-step explanation:

AC = BD

6x+10 = 10x+2

simplify:

subtract 6x and 2 from both sides:

4x = 8

x = 2

then:

AC = 6(2)+10 = 22

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LaTesha and Bernard are playing a game. Their scores for five games are shown in the table below. LaTesha’s and Bernard’s Scores
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Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)
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Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

x^{2} +y^{2}+4x-1=0

Step-by-step explanation:

<u>Explanation:</u>-

<u>Step 1:</u>-

The equation of the circle having center and radius is

(x-h)^2+(y-k)^2=r^2

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

      (\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2}  )

    (-2,0)

therefore center (h,k) = (-2,0)

<u>Step 2:-</u>

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}

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r=\sqrt{5}

<u>Step 3</u>:-

center (h,k) = (-2,0) and

radius r=\sqrt{5}

The standard form of circle equation

(x-h)^2+(y-k)^2=r^2

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on simplification is

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