A decrease of 8.25% means the reduction factor is 100-8.25=91.75%=0.9175.
The shrinkage over 15 years is 0.9175¹⁵=0.27485 approx, so the size of the forest will be 3100×0.27485=852 sq km approx.
Answer:
68 degrees
Step-by-step explanation:
The ladder, the building and the ground together make up a right triangle with angle of elevation to be determined.
The side opposite this angle is 10 ft; the distance of the foot of the ladder from the building is 4 ft. Thus,
tan x = (opp side) / (adj side) = 10/4. Using the inverse tangent function, we find that the angle in question is
arctan (10/4) = 68 degrees
you need to find how much the output changes for each unit change in the input. (ie from an input change from 5 to 6 the output changes by three units and an input change of 3 (2 - 5 ) units the output changes by 9 units). This will give you the gradient of the equation. then you have to find out the y intercept by finding what the output is when the input is 0. Do this by multiplying the input by the gradient and then subtracting it from that inputs output. This will give you the answer A) 3x
(Sorry, its a bit wordy :) )
Answer:
![6A- 8B = \left[\begin{array}{ccc}56&50&-14\\-126&92&62\\-78&26&2\end{array}\right]](https://tex.z-dn.net/?f=6A-%208B%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D56%2650%26-14%5C%5C-126%2692%2662%5C%5C-78%2626%262%5Cend%7Barray%7D%5Cright%5D)
Option A is correct.
Step-by-step explanation:
![A=\left[\begin{array}{ccc}-4&-1&-9\\-9&6&9\\-1&-1&3\end{array}\right] \\B=\left[\begin{array}{ccc}-10&-7&-5\\9&-7&-1\\9&-4&2\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%26-1%26-9%5C%5C-9%266%269%5C%5C-1%26-1%263%5Cend%7Barray%7D%5Cright%5D%20%5C%5CB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-10%26-7%26-5%5C%5C9%26-7%26-1%5C%5C9%26-4%262%5Cend%7Barray%7D%5Cright%5D)
We need to find 6A - 8B
Multiply matrix A with 6 and matrix B with 8 and then subtract 6A - 8B
![6A=\left[\begin{array}{ccc}-24&-6&-54\\-54&36&54\\-6&-6&18\end{array}\right] \\8B=\left[\begin{array}{ccc}-80&-56&-40\\72&-56&-8\\72&-32&16\end{array}\right]\\6A - 8B =\left[\begin{array}{ccc}-24-(-80)&-6-(-56)&-54-(-40)\\-54-(72)&36-(-56)&54-(-8)\\-6-(72)&-6-(-32)&18-(16)\end{array}\right] \\6A - 8B =\left[\begin{array}{ccc}-24+80&-6+56&-54+40\\-54-72&36+56&54+8\\-6-72&-6+32&18-16\end{array}\right] \\6A- 8B = \left[\begin{array}{ccc}56&50&-14\\-126&92&62\\-78&26&2\end{array}\right]](https://tex.z-dn.net/?f=6A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-24%26-6%26-54%5C%5C-54%2636%2654%5C%5C-6%26-6%2618%5Cend%7Barray%7D%5Cright%5D%20%5C%5C8B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-80%26-56%26-40%5C%5C72%26-56%26-8%5C%5C72%26-32%2616%5Cend%7Barray%7D%5Cright%5D%5C%5C6A%20-%208B%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-24-%28-80%29%26-6-%28-56%29%26-54-%28-40%29%5C%5C-54-%2872%29%2636-%28-56%29%2654-%28-8%29%5C%5C-6-%2872%29%26-6-%28-32%29%2618-%2816%29%5Cend%7Barray%7D%5Cright%5D%20%5C%5C6A%20-%208B%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-24%2B80%26-6%2B56%26-54%2B40%5C%5C-54-72%2636%2B56%2654%2B8%5C%5C-6-72%26-6%2B32%2618-16%5Cend%7Barray%7D%5Cright%5D%20%5C%5C6A-%208B%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D56%2650%26-14%5C%5C-126%2692%2662%5C%5C-78%2626%262%5Cend%7Barray%7D%5Cright%5D)
So,
Option A is correct.
