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3 years ago

What is the value of n in the equation shown below? 2^2 x 2^n = (2^4)^3

1 answer:

3 0

So 2^2*2^n=(2^4)^3
2^2= 4
2^4=16
Then 16^3=4096
Now what we have is 4*2^n= 4096
You need to get the 2^n by itself so divide out the 4
4096/4= 1024
2^n=1024
Now you need to do log to get rid of that exponent
Therefore: n=log2(2024) or n=10

ANSWER
n=10

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3 years ago

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3 years ago

Currently 1 United States dollar equals 19.25 Mexican pesos. If you exchanged 725 Mexican pesos for US dollars, what amount woul

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The value of 725 Mexican pesos is equals to 37.66 US dollars

Step-by-step explanation:

Given as :

The value of 1 US dollar equals to 19.25 Mexican pesos

The total amount of Mexican pesos = 725

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∵ 19.25 Mexican pesos equals to 1 US dollars

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3 years ago

Find the midpoint of PQ<br><br> P(4 1/3, 3 1/6), Q(-2 1/5, 3 2/3)

Paha777 [63]

Answer:

$(1\frac{1}{15},3\frac{5}{12})$

Step-by-step explanation:

To find the midpoint, you must average the x's then average the y's.

So the x's are $4 \frac{1}{3}$ and $-2\frac{1}{5}$ .

The y's are $3\frac{1}{6}$ and $3\frac{2}{3}$ .

To find an average of a data with 2 elements you must add the two elements then take that sum and divide it by 2.

So this is what we will do with the x's then the y's.

So first x:

$\frac{4\frac{1}{3}+-2\frac{1}{5}}{2}$

Write as improper fractions:

$\frac{\frac{13}{3}+\frac{-11}{5}}{2}$

Division by 2 is the same as multiplying by 1/2:

$\frac{13}{6}+\frac{-11}{10}$

The least common multiple of 6 and 10 is 30. We will multiply first fraction by 5/5 and 3/3 for the second so we can have the same denominator.

$\frac{65}{30}+\frac{-33}{30}$

Now that the bottoms are the same we can write as one fraction:

$\frac{65+-33}{30}$

Simplify:

$\frac{32}{30}$

If you want the answer as a mix fraction like your question began as we can do that by first figuring out how many 30's are in 32 and what is the remainder of that division.

There is one 30 and 32 and so 32-30=2 is the remainder.

$1\frac{2}{30}$