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Musya8 [376]
3 years ago
10

What is the value of n in the equation shown below? 2^2 x 2^n = (2^4)^3

Mathematics
1 answer:
AlekseyPX3 years ago
3 0
So 2^2*2^n=(2^4)^3
2^2= 4
2^4=16
Then 16^3=4096
Now what we have is 4*2^n= 4096
You need to get the 2^n by itself so divide out the 4
4096/4= 1024
2^n=1024
Now you need to do log to get rid of that exponent
Therefore: n=log2(2024) or n=10

ANSWER
n=10
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