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jonny [76]
3 years ago
13

What is the solution to f(x)=g(x) ? Select each correct answer.

Mathematics
2 answers:
ludmilkaskok [199]3 years ago
5 0
Check the picture below

zheka24 [161]3 years ago
4 0
Just plug in the x values into the equations:
f(x)=4(x)+1= 4(-3)+1 = -11
g(x) = 3^x+1 - 4 = 3^-3+1 - 4 = -35/9
A. True
B. True
C. True
D. True
E. True
F. True
G. True
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50 I think. 2 1/2 times 20 minutes equals 50
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3 years ago
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Joey is creating a rectangular garden. The garden is 9 feet long and 7 feet wide. Joey calculated he needs feet of fencing to cl
Crazy boy [7]

Answer:

Amount of fencing: 32 feet

Amount of soil: 63 square feet

Step-by-step explanation:

Fencing: In a rectangle, the opposite side is the same length. So we do:

9+7+9+7 = <u>32 feet</u>

Soil: The soil is the area. Area is equal to length times width. Length is 9 and width is 7, so we do:

9 x 7 = <u>63 feet squared</u>

8 0
4 years ago
Carnival T charges an entrance fee of $7.00 and $0.50 per ticket for the rides. Carnival Q charges an entree fee of $12.00 and $
FrozenT [24]

Answer:

$30

Step-by-step explanation:

Calculation for the tickets that must be purchased for Carnival T and Carnival Q to be the same

Based on the information given let x be the number of ticket to be purchased .

Carnival T entrance fee= $7.00

Ride= $0.50 per ticket

Carnival Q entree fee =12.00

Ride= $0.25 per ticket

Tickets=$7.00 + ($0.50* x) = $12.00 + ($0.25* x)

.25 x = 5.00

Hence:

x=$.25+$5.00

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Therefore the amount of tickets that must be purchased in order for the total cost at Carnival T and Carnival Q to be the same will be $30

3 0
3 years ago
What is the product of the binomals below (2x+3) (3x+3)
Korvikt [17]

Answer:

3*(2x+3)*(x+1)

Step-by-step explanation:

pull like terms from the problem to re-arrange it into a product

\left(2x+3\right)\left(3x+3\right)\\3x + 3  =   3 \cdot (x + 1)\\3 \cdot (2x + 3) \cdot (x + 1)\\

5 0
2 years ago
Write in simplest radical form: √208
Arte-miy333 [17]

208:2=104\\104:2=52\\52:2=26\\26:2=13\\13:13=1\\\\208=2\cdot2\cdot2\cdot2\cdot13=2^2\cdot2^2\cdot13\\\\\sqrt{208}=\sqrt{2^2\cdot2^2\cdot13}=\sqrt{2^2}\cdot\sqrt{2^2}\cdot\sqrt{13}=2\cdot2\cdot\sqrt{13}=4\sqrt{13}\\\\Answer:\ \sqrt{208}=4\sqrt{13}\\\\Used:\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{a^2}=a

6 0
4 years ago
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