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Jet001 [13]
3 years ago
8

Somebody help!!!! DON'T UNDERSTAND!!!!!! What am I getting wrong!?!

Mathematics
1 answer:
Natali [406]3 years ago
5 0

Answer:

2x ^5  sqrt( 6x)

Step-by-step explanation:

sqrt( 3 x^4)  * sqrt( 8 x^7)

Multiply them together

sqrt( 3x^4 * 8x^7)

sqrt( 24 x^ (4+7))

sqrt( 24 x^11)

We can simplify

sqrt(24) sqrt(x^11)

sqrt( 4*6) sqrt( x^10) sqrt(x)

sqrt(4) sqrt(6)   x^5sqrt(x)

2 sqrt(6)  x^5sqrt( x)

Combining the square roots

2x ^5  sqrt( 6x)

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The following two-way table describes student's
guajiro [1.7K]

P ( work/ senior ) = 0.14

The attached table

required

P ( work/ senior )

This is calculated using:

P ( work/ senior ) = n ( work/ senior )/ n ( senior ).

n ( work/ senior ) = 5

n ( senior ) = 25 + 5 + = 35

So:

P ( work/ senior ) = 5/35

P ( work/ senior ) = 0.14

Add 25+5+5 (because that is all the numbers in the 'Seniors' row) and then take the 5 that is in the 'Work' column and put that over 25. (5/25 fraction as a percent is 14).

Learn more about probability at

brainly.com/question/24756209

#SPJ4

7 0
1 year ago
The sum of two consecutive odd integers is 20 less than four times the smaller of the two integers. Which the following equation
Rudiy27

Answer:

consecutive = x+x+2

x+x+2 = 4x-20

2x+2=4x-20

2=2x-20

22=2x

x=11

Numbers are 11,13.

Hope this helps plz hit the crown :D

8 0
3 years ago
Solve the equation<br><br> 1.6=7.6-5(k+1.1)
zepelin [54]
7.6 - 5(k + 1.1) = 1.6

7.6 - 5(k + 1.1) - 7.6 = 1.6 - 7.6

-5(k +1.1) = -6

-5(k + 1.1) -6
-------------- = ---------
-5 -5

k + 1.1 = 6
-----
5

k + 1.1 - 1.1 = 6
----- - 1.1
5

k = 0.1
8 0
2 years ago
How do I solve 6v-5/8=7/8
astra-53 [7]
6v-5/8=7/8
6v=12/8
v=12/8÷6
v=.25
3 0
3 years ago
−2x=x^2 minus 6, <br> Rewrite the equation by completing the square. please answer
Paul [167]

Answer:

(x+1)^{2} -5

Step-by-step explanation:

-2x=x^{2} -6 \\x^{2} +2x-6\\(\frac{b}{2}) ^{2} =(\frac{2}{2}) ^{2} =1^{2} =1\\so, (x^{2} +2x+1)-6+1\\ x^{2} +2x+1=(x+1)^{2} \\-6+1=5\\(x+1)^{2} -5

Sorry it took so long

4 0
3 years ago
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