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svp [43]
3 years ago
13

Find the percent of increase from 1.5 inches to 6 inches.

Mathematics
1 answer:
jeyben [28]3 years ago
7 0
Since 6/1.5 is 4. It increased 400%.
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An airliner maintaining a constant elevation of 2 miles passes over an airport at noon traveling 500 mi/hr due west. At 1:00 PM,
butalik [34]

Answer:

\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}

Step-by-step explanation:

Let suppose that airliners travel at constant speed. The equations for travelled distance of each airplane with respect to origin are respectively:

First airplane

r_{A} = 500\,\frac{mi}{h}\cdot t\\r_{B} = 550\,\frac{mi}{h}\cdot t

Where t is the time measured in hours.

Since north and west are perpendicular to each other, the staight distance between airliners can modelled by means of the Pythagorean Theorem:

s=\sqrt{r_{A}^{2}+r_{B}^{2}}

Rate of change of such distance can be found by the deriving the expression in terms of time:

\frac{ds}{dt}=\frac{r_{A}\cdot \frac{dr_{A}}{dt}+r_{B}\cdot \frac{dr_{B}}{dt}}{\sqrt{r_{A}^{2}+r_{B}^{2}} }

Where \frac{dr_{A}}{dt} = 500\,\frac{mi}{h} and \frac{dr_{B}}{dt} = 550\,\frac{mi}{h}, respectively. Distances of each airliner at 2:30 PM are:

r_{A}= (500\,\frac{mi}{h})\cdot (1.5\,h)\\r_{A} = 750\,mi

r_{B}=(550\,\frac{mi}{h} )\cdot (1.5\,h)\\r_{B} = 825\,mi

The rate of change is:

\frac{ds}{dt}=\frac{(750\,mi)\cdot (500\,\frac{mi}{h} )+(825\,mi)\cdot(550\,\frac{mi}{h})}{\sqrt{(750\,mi)^{2}+(825\,mi)^{2}} }

\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}

6 0
3 years ago
Find mZXZx(5t - 13°Y(3t+ 3)
trapecia [35]

The diagram provided is an isosceles triangle. An isosceles triangle has two sides having equal measure and two base angles also having equal measure.

From the marks on the triangle given, line ZX and line ZY are equal in length. This also means angle X and angle Y are equal in measure.

Therefore, we would have;

\begin{gathered} 5t-13=3t+3 \\ \text{Collect all like terms and you'll have,} \\ 5t-3t=3+13 \\ 2t=16 \\ \text{Divide both sides by 2} \\ \frac{2t}{2}=\frac{16}{2} \\ t=8 \\ \text{If t=8, then} \\ 5t-13=5(8)-13 \\ 5t-13=40-13 \\ 5t-13=27 \end{gathered}

This means angle X and angle Y both equal 27 degrees each.

Note that the sum of angles in a triangle is 180. Therefore, in triangle ZXY,

undefined

7 0
10 months ago
Two wires
xz_007 [3.2K]

Answer:

am i suppoesd to do number 7 as well?

Step-by-step explanation:

Two wires

tether a balloon to the ground, as shown. How

high is the balloon above the ground? (Must Use Right

Triangle Trigonometry)

look at picture

4 0
3 years ago
What is the area of the triangle? (Pls help thx)
Anna [14]
To solve for the area of the triangle 
Use the formula 1/2(base *height)
1/2 * 17* 4
68/2
34

I believe the area of the triangle is therefore 34ft
5 0
3 years ago
When written in standard form, the quadratic equation, x2 - 2x - 35 = 0, is equivalent to y = (x - 1)2 - 36. What is the vertex
horrorfan [7]
 y = a(x - b)^2 + c     has vertex  (b , c)

so here the vertex is (1, -36)
6 0
3 years ago
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