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Blizzard [7]
4 years ago
6

Y=×^2+4x+1 and y=x+1 Solve a linear/quadratic system by graphing and substitution.

Mathematics
1 answer:
LiRa [457]4 years ago
8 0
Graphing is used when you have paper

I will not graph this equation because it takes time, sorry

but I will solve

subsitute y=x^2+4x+1
subsitute x+1 for y
x+1=x^2+4x+1
subtract x from bot sides
1=x^2+3x+1
subtract 1 from both sides
0=x^2+3x
factor
0=(x)(x+3)
if xy=0 then assume that x and y=0
so
set them to zero
x=0

x+3=0
subtract 3 from both sides
x=-3

subsitue
y=x+1
y=0+1
y=1

y=-3+1
y=-2

so the answers could be
(x,y)
(-3,-2)
(0,1)
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Since the center point is (-2,6), the numbers are reversed in the equation to: (x+2) or(x- -2) and (y-6)

The radius is 6 units so u square it to get 36
7 0
4 years ago
How many sixteenths are in 15/16
katovenus [111]
There are 15 sixteenths in 15/16.
8 0
3 years ago
Read 2 more answers
1=n+1/3 (please show your work!)
lubasha [3.4K]
N is 2/3 because 1 minus 1/3 is 2/3
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(All yes or no questions). Determine whether each of the following pairs of angles have equal measures:
erica [24]

9514 1404 393

Answer:

  a) no

  b) yes

  c) yes

  d) no

Step-by-step explanation:

Angle LJM is complementary to KJL, so is ...

  angle LJM = 90° -42° = 48°

Angle NJP is marked as congruent to angle PJQ, so is also 48°.

__

a) ∠KJL = 42° ≠ 48° = ∠LJM . . . . NO

b) ∠MJP = 46°+48° = 48° +46° = ∠PJR . . . . YES

c) ∠LJP = 48° +46° +48° = 48° +48° +46° = ∠NJR . . . . YES

d) ∠MJK = 90° ≠ 48° +46° = ∠PJR . . . . NO

6 0
3 years ago
Students in Mrs. Marquez's class are watching a film on the uses of geometry
Oxana [17]

The given information on the diagram of the projector and the image can

be used to prove the congruency of the triangles.

∠ABD, ∠BDA, and side \overline {AD} on ΔABD are congruent to ∠CBD, ∠BDC, and

segment \overline {CD} on ΔCBD, therefore, ΔABD ≅ ΔCBD, by <u>AAS Theorem</u>

Reasons:

The figure of the projector that casts an image on the screen is attached.

The bisector of the line \overline {AC} = \overline {BD}

From the drawing, we have;

∠ABD ≅ ∠CBD by equal number arc mark.

The two column proof is therefore, presented as follows;

Statement {}                                            Reason

\overline {BD} is perpendicular bisector of   {}\overline {AC}   Given

\overline {AD} = \overline {CD}   {}                                             Definition of bisected line \overline {AC}  

∠BDC = 90°       {}                                      \overline {BD} is perpendicular \overline {AC}  

∠BDA = 90°                         {}                    \overline {BD} is perpendicular \overline {AC}  

∠ABD ≅ ∠CBD {}                                       Given on the diagram

ΔABD ≅ ΔCBD  {}                          by Angle-Angle-Side AAS Congruency rule

The Angle-Angle-Side, AAS, Congruency postulate states that two

triangles are congruent where two adjacent angles and a non included side

on one triangle are congruent to the corresponding two adjacent angles

and a non included side on the other triangle.

Learn more here:

brainly.com/question/15274307

8 0
3 years ago
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