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yanalaym [24]
3 years ago
15

Can someone help me answer this??

Mathematics
2 answers:
Rus_ich [418]3 years ago
4 0

Answer:

That would indicate 20.0 ml

id appreciate a rating thanks XP

Tasya [4]3 years ago
3 0

Answer:

hkkr

need school the long said

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Match the equation with its graph . identify the slope and y-intercept y= -2/3x+1
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Answer:

the slope is -2/3x and the y intercept is 1

Step-by-step explanation:

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A box of pens cost $6.50 and a box of pencils is $4.00. Jane gets 15% commission of each box of pencils sold. Calculate Jane's c
lys-0071 [83]

Answer:

10.50

Step-by-step explanation:

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Need help please ! parallelogram
OverLord2011 [107]

Answer:

11). m∠W = 70°

12). m∠M = 95°

13). m∠Q = 135°

14). m∠Q = 55°

15). m∠X = 110°

Step-by-step explanation:

11). m∠W + m∠X = 180° [Consecutive interior angles]

    (24x - 2) + (36x + 2) = 180°

     60x = 180°

     x = \frac{180}{60}

     x = 3

     Therefore, m∠W = (24x - 2)°

     m∠W = (24×3 - 2)

               = 72 - 2

               = 70°

     Since opposite angles of a parallelogram are equal in measure.

     m∠Y = m∠W = 70°

12). m∠J + m∠K = 180° [Consecutive interior angles]

     (6x + 19) + (8x + 7) = 180°

     14x + 26 = 180

     14x = 180 - 26

     14x = 154

     x = \frac{154}{14}

     x = 11

     m∠K = (8x + 7)

     m∠K = 8×11 + 7

     m∠K = 95°

     Since m∠M = m∠K

     Therefore, m∠M = 95°

13). m∠Q = m∠S [Opposite angles of a parallelogram]

      x + 135 = 2x + 135

      2x - x = 0

      x = 0

      Therefore, m∠Q = 135°

14). m∠Q = m∠S [Opposite angles of a parallelogram]

      14x - 1 = 13x + 3

      14x - 13x = 3 + 1

      x = 4

      m∠Q = (13x + 3)

                = 13×4 + 3

                = 52 + 3

      m∠Q = 55°

15). m∠Z = m∠X

     (19x - 4) = (17x + 8)

      19x - 17x = 12

      2x = 12

      x = 6

      m∠X = (17x + 8)°

      m∠X = 17×6 + 8

      m∠X = 110°

5 0
2 years ago
Verify identity: <br><br> (sec(x)-csc(x))/(sec(x)+csc(x))=(tan(x)-1)/(tan(x)+1)
Nikitich [7]
So hmmm let's do the left-hand-side first

\bf \cfrac{sec(x)-csc(x)}{sec(x)+csc(x)}\implies \cfrac{\frac{1}{cos(x)}-\frac{1}{sin(x)}}{\frac{1}{cos(x)}+\frac{1}{sin(x)}}\implies &#10;\cfrac{\frac{sin(x)-cos(x)}{cos(x)sin(x)}}{\frac{sin(x)+cos(x)}{cos(x)sin(x)}}&#10;\\\\\\&#10;\cfrac{sin(x)-cos(x)}{cos(x)sin(x)}\cdot \cfrac{cos(x)sin(x)}{sin(x)+cos(x)}\implies \boxed{\cfrac{sin(x)-cos(x)}{sin(x)+cos(x)}}

now, let's do the right-hand-side then  

\bf \cfrac{tan(x)-1}{tan(x)+1}\implies \cfrac{\frac{sin(x)}{cos(x)}-1}{\frac{sin(x)}{cos(x)}+1}\implies \cfrac{\frac{sin(x)-cos(x)}{cos(x)}}{\frac{sin(x)+cos(x)}{cos(x)}}&#10;\\\\\\&#10;\cfrac{sin(x)-cos(x)}{cos(x)}\cdot \cfrac{cos(x)}{sin(x)+cos(x)}\implies \boxed{\cfrac{sin(x)-cos(x)}{sin(x)+cos(x)}}

7 0
2 years ago
A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of t
11Alexandr11 [23.1K]

Answer:

  • <u>Question 1:</u>      dm/dt=0.2m<u />

<u />

  • <u>Question 2:</u>     m=Ae^{(0.2t)}<u />

<u />

  • <u>Question 3:</u>      m=10e^{(0.2t)}<u />

<u />

  • <u>Question 4:</u>      m=10g<u />

Explanation:

<u>Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m</u>

<u></u>

a) By definition:  m'=dm/dt

b)  Given:  rate=0.2m

c) By substitution:  dm/dt=0.2m

<u>Question 2: Find the general solution of this equation. Use A as a constant of integration.</u>

a) <u>Separate variables</u>

     dm/m=0.2dt

b)<u> Integrate</u>

           \int dm/m=\int 0.2dt

            ln(m)=0.2t+C

c) <u>Antilogarithm</u>

       m=e^{0.2t+C}

       m=e^{0.2t}\cdot e^C

         e^C=A\\\\m=Ae^{(0.2t)}

<u>Question 3. Which particular solution matches the additional information?</u>

<u></u>

Use the measured rate of 4 grams per hour after 3 hours

            t=3hours,dm/dt=4g/h

First, find the mass at t = 3 hours

            dm/dt=0.2m\\\\4=0.2m\\\\m=4/0.2\\\\m=20g

Now substitute in the general solution of the differential equation, to find A:

          m=Ae^{(0.2t)}\\\\20=Ae^{(0.2\times 3)}\\\\A=20/e^{(0.6)}\\\\A=10.976

Round A to 1 significant figure:

  • A = 10.

<u>Particular solution:</u>

           

             m=10e^{(0.2t)}

<u>Question 4. What was the mass of the bacteria at time =0?</u>

Substitute t = 0 in the equation of the particular solution:

         m=10e^{0}\\\\m=10g

3 0
3 years ago
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